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Grace [21]
4 years ago
9

Give the formulas for the ionic compounds made of the following ions:

Chemistry
1 answer:
mezya [45]4 years ago
5 0
ScBr3, K2O, CaI2, Cr2S3, RbF, MgO, K3N, SrF2, and Al2S3. The only thing you need to do is to ensure every ionic compound has a total valence of zero. Four the last four, you need to know usually valence of these ions.
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2. A quantity of 1.922g of methanol (CH3OH) was burned in a constant-volume
Cerrena [4.2K]
Mass of methanol (CH3OH) = 1.922 g
Change in Temperature (t) = 4.20°C
Heat capacity of the bomb plus water = 10.4 KJ/oC
The heat absorbed by the bomb and water is equal to the product of the heat capacity and the temperature change.
Let’s assume that no heat is lost to the surroundings. First, let’s calculate the heat changes in the calorimeter. This is calculated using the formula shown below:
qcal = Ccalt
Where, qcal = heat of reaction
Ccal = heat capacity of calorimeter
t = change in temperature of the sample
Now, let’s calculate qcal:
qcal = (10.4 kJ/°C)(4.20°C)
= 43.68 kJ
Always qsys = qcal + qrxn = 0,
qrxn = -43.68 kJ
The heat change of the reaction is - 43.68 kJ which is the heat released by the combustion of 1.922 g of CH3OH. Therefore, the conversion factor is:
5 0
3 years ago
Elements that share properties of both metals and nonmetals?
maw [93]
I can help with that!
<span>-Boron (B)
-Silicon (Si)
-Germanium (Ge)
-Arsenic (As)
-Antimony (Sb)
-Tellurium (Te)
-Polonium (Po)
<span>-Astatine (At)</span></span>
7 0
4 years ago
Read 2 more answers
How many cm are in 3.1 mi
grandymaker [24]
It would be 498896.64 cm
5 0
3 years ago
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A gas mixture contains 0.700 mol of N2, 0.300 mol of H2, and 0.400 mol of CH4. Calculate the pressure of the gas mixture and the
Nitella [24]

Answer:

Pressure of the gas mixture: 4.30 atm

Partial pressure N₂ = 2.15 atm

Partial pressure H₂ =  0.91 atm

Partial pressure CH₄ = 1.23 atm

Explanation:

To determine partial pressure we sum the total moles in order to find out the total pressure

We can work with mole fraction

We apply the Ideal Gases Law

0.700 N₂ + 0.300 H₂ + 0.400 CH₄ = 1.4 moles

We replace data  → P . V = n . R .T

T° must be at K →  27  °C + 273 = 300 K

P . 8 L = 1.4 mol . 0.082 L.atm/mol.K  . 300 K

P = ( 1.4 mol . 0.082 L.atm/mol.K  . 300 K) / 8 L = 4.30 atm (Total pressure)

We apply the mol the fraction for the partial pressure

Moles x gas / total moles = partial pressure x gas / total pressure

Mole fraction N₂ → 0.700 /1.4 = 0.5

Partial pressure N₂ = 0.5 . 4.30 atm =2.15 atm

Mole fraction H₂  →  0.300 / 1.4 = 0.21

Partial pressure H₂ = 0.21 . 4.30 atm = 0.91 atm

Mole fraction CH₄ → 0.400 /1.4 = 0.28

Partial pressure CH₄ = 0.28 . 4.30 atm =1.23 atm

7 0
4 years ago
Read 2 more answers
What happens when two areas of air have different pressures?
Novosadov [1.4K]

A low pressure system has lower pressure at its center than the areas around it. Winds blow towards the low pressure, and the air rises in the atmosphere where they meet.

3 0
3 years ago
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