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nlexa [21]
3 years ago
12

An blank Used to determine the change of an object

Physics
1 answer:
madam [21]3 years ago
7 0
The acceleration is used to determine the change of an object.
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Help with 5-10 please
Zina [86]

Answer:

explained in attachment

Explanation:

explained in attachment

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5 0
3 years ago
Reduce<br> Reflects<br> Transfers<br> Stops
Bond [772]
I think transfers is the answer
4 0
3 years ago
Calculate the acceleration of a bus that goes
Svet_ta [14]

The acceleration of the bus is 1.11 meters per second square to the direction of motion

Explanation:

Acceleration is the rate of change of velocity

The formula of the acceleration is a=\frac{v_{2}-v_{1}}{t} , where

  • v_{1} is the initial velocity
  • v_{2} is the final velocity
  • t is the time

A bus that goes  from 10 km/h to a speed of 50 km/h in 10 seconds

→ v_{1} = 10 km/h

→ v_{2} = 50 km/h

→ t = 10 seconds

Change the unite of the time from seconds to hour

→ 1 hour = 60 × 60 = 3600 seconds

→ 10 seconds = \frac{10}{3600}=\frac{1}{360} hour

Substitute these values in the formula of the acceleration above

→ a=\frac{50-10}{\frac{1}{360}}

→ a = 14400 km/h²

To change the unit of acceleration to meter per second change the

  kilometer to meter and the hour to seconds

→ 1 km = 1000 m

→ 1 hour = 3600 seconds

→ a=\frac{14400*1000}{(3600)^{2}}=\frac{10}{9}

→ a = 1.11 m/sec².

The acceleration of the bus is 1.11 meters per second square to the direction of motion

Learn more:

You can learn more about the acceleration in brainly.com/question/6323625

#LearnwithBrainly

4 0
4 years ago
A falcon can descend with a speed 250 km/h. If a falcon flies at this speed for 2.0 s and then flies a 100 m in 2.5 s, what is t
Vadim26 [7]

Answer:

v= s/t

Explanation:

250 km/ h =69.44m/s

S1=2 times 69.44 ≈ 139m

Next 2.5 seconds:

S2 = 100m

Average speed:

v=139m+100m/2s+2.5s = 239/4.5s = 53.2 m/s=192km/h

3 0
3 years ago
A capacitor is charged until its stored energy is 7.54 J. A second capacitor is then connected to it in parallel. If the charge
Ivan

Answer:

2 J

Explanation:

A charged capacitor of capacitance C_1 with energy of 7.54 J, is connected in parallel with another capacitor C_2 , so the charge is equally distributed between them.

(a) The energy stored in the capacitor before it being connected to the other capacitor is:

U_O=q_0^2/2C_1=7.54 J\\

The energy stored in the electric field is the sum of the energies of the two capacitors:

U=U_1+U_2\\U=q_1^2/2C_1+q_2^2/2C_2

since the charge equally distributed,  q_1 = q_2 = q_o/2. and since they are connected in parallel the potential difference on both of them is the same :

V_1=V_2\\q_1/C_1=q_2/C_2\\q_0/C_1=q_0/C_2\\C_1=C_2=C_3\\

hence,

U=q_0^2/8C+q_0^2/8C\\U=q_0^2/4C\\U=2J

8 0
3 years ago
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