Question

A wire carries a current of 4.1 A. How many electrons per second are passing any cross sectional area of the wire? Enter your answer in the format *.**E** (for example, the fundamental unit of charge, which is 1.60 cross 10^(-19) C, would be entered by typing 1.60E-19). electrons per second

Answer 1

To solve this problem it is necessary to apply the concepts related to Current and Load.

The current in terms of the charge of an electron can be expressed as

$i = \frac{q}{t}$

Where,

q = Charge

t = time

At the same time the Charge is the amount of electrons multiplied by the amount of these, that is

q = ne

Replacing in the first equation we have to

$i = \frac{q}{t}$

$i = \frac{ne}{t}$

Clearing n,

$n = \frac{it}{e}$

Here the time is one second then

$n = \frac{i}{e}$

$n = \frac{4.1}{1.6*10^{-9}}$

$n = 2.56*10^{19}electrons$

Therefore the number of electrons per second are passing any cross sectional area of the wire are $2.56*10^{19}electrons$