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koban [17]
3 years ago
5

Mention five disadvantages of nonsustainable energy ​

Physics
1 answer:
Hitman42 [59]3 years ago
7 0

Answer:

Explanation:

Even as our global society makes a push toward renewable energy through accords like the Paris agreement, there is still a place in our society for non-renewables.

Fossil fuels give us a way to maintain our current infrastructure while we start developing new ways to produce clean energy. Solar, wind, water, and geothermal resources are all possible because of the manufacturing practices that we have today that use non-renewables.

The definition of a non-renewable energy source is straightforward. If you consume the item and it no longer becomes available for use, then it qualifies as this resource. Renewables are resources that are always present in some way.

As new technologies allow us to be more efficient with our fossil fuels, a review of the advantages and disadvantages of non-renewable energy gives us a way to examine this still essential resource.

List of the Advantages of Non-Renewable Energy

1. We can prepare non-renewable supplies at almost any location.

If we want to control energy from renewables, then we must identify regions globally that support this outcome. This issue applies to solar, wind, and even geothermal for some geographic locations. Some locations are not well-suited to the production of renewable energy.

It is not an issue for non-renewables because we can develop processing stations everywhere to establish their refinement and distillation. Although problems with transport loss occur when using them, a well-developed infrastructure can reduce this predicament rather effectively.

2. Non-renewables produce more power after the refinement process.

When we process non-renewables to seize the energy potential offered, we can generate more power from crude oil, natural gas, and other fuels than what they provide in their raw format.

If we take a single barrel of crude oil, then it provides 42 gallons of product to use at our discretion. When we complete the work of preparing this non-renewable, then the yield gives us the equivalent of more than 44 gallons of finished products. That means we attain 6% more energy potential when using fossil fuels, and that’s a total that renewables can’t replicate.

3. Thousands of unique products come from non-renewables.

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Answer:

a) 2.00024 m

b) 0.036%

c) 436.67°C

Explanation:

Given

Initial length = L₀ = 2 m

Initial cross sectional Area = A₀ = 200 cm² = 0.02 m²

We can obtain initial volume = V₀ = A₀L₀ = 0.02 × 2 = 0.04 m³

Initial Temperature = T₀ = 20°C

Coefficient of linear expansivity = α = (2 × 10⁻⁶) (°C)⁻¹

a) New length of the rod after heating to 80°C

Linear expansion is given as

ΔL = L₀ × α ×ΔT

ΔL = 2 × 2 × 10⁻⁶ × (80 - 20) = 0.00024 m = 0.24 mm

New length = old length + expansion = 2 + 0.00024 = 2.00024 m

b) The percentage of the volume change of the rod.

Volume expansion is given by

ΔV = V₀ × (3α) × ΔT

Volume expansivity ≈ 3 × (linear expansivity)

ΔV = 0.04 × (3×2×10⁻⁶) × (80 - 20) = 0.0000144 m³

Percentage change in volume = 100% × (ΔV/V₀) = 100% × (0.0000144/0.04) = 0.036%

c) The maximal temperature we can allow if the volume should not increase by more than half percent.

For a half percent increase in volume, the corresponding change in volume needs to be first calculated.

Percentage change in volume = 100% × (ΔV/V₀)

0.5 = 100% × (ΔV/0.04)

(ΔV/0.04) = 0.005

ΔV = 0.0002 m³

Then we now investigate the corresponding temperature that causes this.

ΔV = V₀ × (3α) × ΔT

0.0002 = 0.04 × (3×2×10⁻⁶) × ΔT

ΔT = (0.0002)/(0.04 × 3 × 2 × 10⁻⁶) = 416.67°C

Maximal temperature = T₀ + ΔT = 20 + 416.67 = 436.67°C

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2 years ago
A uniform electric field with a magnitude of 5750 N/C points in the positive x direction. Find the change in electric potential
castortr0y [4]

Explanation:

Given that,

Electric field = 5750 N/C

Charge q=+10.5\times10^{-6}\ C

Distance = 5.50 cm

(a). When the charge is moved in the positive x- direction

We need to calculate the change in electric potential energy

Using formula of electric potential energy

\Delta U=-W

\Delta U=-F\cdot d

\Delta U=-q(E\cdot d)

Put the value into the formula

\Delta U=-10.5\times10^{-6}\times5750\times5.50\times10^{-2}

\Delta U=-3.32\times10^{-3}\ J

The change in electric potential energy  is -3.32\times10^{-3}\ J

(b). When the charge is moved in the negative x- direction

We need to calculate the change in electric potential energy

Using formula of electric potential energy

\Delta U=-W

\Delta U=-F\cdot (-d)

\Delta U=-q(E\cdot (-d))

Put the value into the formula

\Delta U=-10.5\times10^{-6}\times5750\times(-5.50\times10^{-2})

\Delta U=3.32\times10^{-3}\ J

The change in electric potential energy  is 3.32\times10^{-3}\ J

Hence, This is the required solution.

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How does the magnitude of the electrical force between a pair of charged particles change when they are brought to half their or
Ostrovityanka [42]

Answer:

5. Quadruple

Explanation:

The electrostatic force between two charged particles is given by:

F=k\frac{q_1 q_2}{r^2}

where

k is the Coulomb's constant

q1, q2 are the two charges

r is the separation between the charges

If the distance between the charges is reduced to half,

r' = \frac{r}{2}

So the new force will be

F'=k\frac{q_1 q_2}{(r/2)^2}=4(k\frac{q_1 q_2}{r^2})=4F

So, the force will quadruple.

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