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2 years ago

Lines in one spectral series can overlap lines in another.

Chemistry

1 answer:

makvit [3.9K]2 years ago

7 0

The range of wavelengths of the two series shows that the lines in these two series do not overlap.

<h3>What is Wavelength? </h3>

Wavelength is the distance between two successive curves of a wave. They are the forms of radiation of electromagnetic waves like light waves, radio waves, or heat waves and the distance to the highest peak of the wave is the wavelength. The lights that are visible usually have a wavelength of 400-700 nanometers. For example, when a person shares the same attitude and communicates well with another person. It acts like a yardstick to measure radiation. We measure them from the bottom of one wave to the bottom of the next wave.

To learn more about wavelengths, visit: brainly.com/question/13533093

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ICE Princess25 [194]

Their radiation facilitates nuclear fusion in young stars.

7 0

3 years ago

Read 2 more answers

Write the uses of all elements which are given in the periodic table

Karolina [17]

Answer:

write the uses of all elements which are given in the periodic table

6 0

3 years ago

A solution is made by dissolving

AVprozaik [17]

Answer:

0.342 m

Explanation:

From the question given above, the following data were obtained:

Mass of NaBr = 14.57 g

Mass of water = 415 g

Molar mass of NaBr = 102.89 g/mol

Molality of NaBr =?

Next, we shall determine the number of mole in 14.57 g of NaBr. This can be obtained as follow:

Mass of NaBr = 14.57 g

Molar mass of NaBr = 102.89 g/mol

Mole of NaBr =?

Mole = mass / molar mass

Mole of NaBr = 14.57 / 102.89

Mole of NaBr = 0.142 mole

Next, we shall convert 415 g of water to kg. This can be obtained as follow:

1000 g = 1 Kg

Therefore,

415 g = 415 g × 1 Kg / 1000 g

415 g = 0.415 Kg

Thus, 415 g is equivalent to 0.415 Kg.

Finally, we shall determine Molality of the solution as follow:

Mole of NaBr = 0.142 mole

Mass of water = 0.415 Kg

Molality of NaBr =?

Molality = mole / mass of water in Kg

Molality of NaBr = 0.142 / 0.415

Molality of NaBr = 0.342 m

Therefore, the molality of NaBr solution is 0.342 m.

5 0

3 years ago

Consider a galvanic cell based on the reaction Al^3+_(aq) + Mg_(s) rightarrow Al_(s) + Mg^2+ _(aq) The half-reactions are Al^3+

grin007 [14]

<u>Answer:</u> The standard cell potential of the cell is -0.71 V

<u>Explanation:</u>

The half reactions follows:

<u>Oxidation half reaction:</u> $Mg\rightarrow Mg^{2+}+2e^-;E^o_{Mg^{2+}/Mg}=-2.37V$ ( × 3)

<u>Reduction half reaction:</u> $Al^{3+}(aq.)+3e^-\rightarrow Al(s);E^o_{Al^{3+}/Al}=-1.66V$ ( × 2)

The balanced cell reaction follows:

$2Al^{3+}(aq.)+3Mg(s)\rightarrow 2Al(s)+3Mg^{2+}(aq.)$

To calculate the $E^o_{cell}$ of the reaction, we use the equation:

$E^o_{cell}=E^o_{cathode}-E^o_{anode}$

Substance getting oxidized always act as anode and the one getting reduced always act as cathode.

Putting values in above equation, we get:

$E^o_{cell}=-2.37-(-1.66)=-0.71V$

Hence, the standard cell potential of the cell is -0.71 V

8 0

3 years ago

An airplane travels with a constant velocity of 210 m/s and in the upper atmosphere where the plane is traveling there is a wind

kolezko [41]

Answer:

hello your question is incomplete the options are missing

Determine the resultant velocity for the plane when it is travelling

i) To the east

ii) To the west

answer :i) 270 i

ii) -150 i

Explanation:

velocity of Airplane = 210 m/s

wind velocity = 60 m/s to the east

The resultant velocity for the plane when it is travelling

let the velocity of the wind = V2

velocity of the plane = v1

i) The resultant velocity for the plane when travelling to the east

Vr = V2 i + V1 i

Vr= 60i + 210i = 270i

ii) resultant velocity when the plane is travelling to the west

Vr = - V1 i + V2i

= -210i + 60 i = -150 i

4 0

3 years ago