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zloy xaker [14]
1 year ago
15

Particle dislodgement in the filtration process is generally undesirable, except during?

Physics
1 answer:
Sedaia [141]1 year ago
4 0

Particle dislodgement in the filtration process is generally undesirable, except during high pressure jets of water applied to filter media during a backwash.

<h3>Define filtration process. </h3>

Filtration is a physical separation procedure that uses a filter medium with a complicated structure that only allows fluid to pass through it to separate solid particles and liquid from a combination. Filtrate is the term for the liquid that passes through the filter medium and is used to describe solid particles that are too large to pass. Larger-than-average particles have the potential to blind the filter by blocking the filter lattice and forming a filter cake on top of the filter. The term "effective pore size" refers to the size of the biggest particles that may successfully pass through a filter.

To know more about filtration, visit:

brainly.com/question/4336354

#SPJ4

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All of the following are true about scientific evidence except: *
goldenfox [79]

Answer:

Your answer is D It does not need to be repeatable.

the reason for this is because C is correct.

You need to be able to experiment on something multiple times so that you can gather further data to imbedded your evidence in facts.

4 0
3 years ago
A flywheel in a motor is spinning at 590 rpm when a power failure suddenly occurs. The flywheel has mass 40.0 kg and diameter 75
Gnom [1K]

Answer:

Explanation:

Hello,

Let's get the data for this question before proceeding to solve the problems.

Mass of flywheel = 40kg

Speed of flywheel = 590rpm

Diameter = 75cm , radius = diameter/ 2 = 75 / 2 = 37.5cm.

Time = 30s = 0.5 min

During the power off, the flywheel made 230 complete revolutions.

∇θ = [(ω₂ + ω₁) / 2] × t

∇θ = [(590 + ω₂) / 2] × 0.5

But ∇θ = 230 revolutions

∇θ/t = (530 + ω₂) / 2

230 / 0.5 = (530 + ω₂) / 2

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460 = 295 + 0.5ω₂

ω₂ = 330rpm

a)

ω₂ = ω₁ + αt

but α = ?

α = (ω₂ - ω₁) / t

α = (330 - 590) / 0.5

α = -260 / 0.5

α = -520rev/min

b)

ω₂ = ω₁ + αt

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t = 590 / 520

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8 0
3 years ago
Three charges are enclosed inside a spherical closed surface. The net flux through the surface is −216 N · m2/C. If two of the c
sladkih [1.3K]

Answer:

q₃ = -4.81 nC

Explanation:

We can use the Gauss Law here:

∅ = q/∈₀

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q = total charge enclosed inside sphere = ?

∈₀ = permittivity of free space = 8.85 x 10⁻¹² C/N.m²

Therefore,

- 216 N.m²/C = q / 8.85 x 10⁻¹² C²/N.m²

q = (-216 N.m²/C)(8.85 x 10⁻¹² C²/N.m²)

q = - 1.91 nC

So, the total charge will be sum of all three charges:

q = q₁ + q₂ + q₃

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q₃ = - 1.91 nC - 1.74 nC - 1.16 nC

<u>q₃ = -4.81 nC</u>

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