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10 months ago

Particle dislodgement in the filtration process is generally undesirable, except during?

1 answer:

4 0

Particle dislodgement in the filtration process is generally undesirable, except during high pressure jets of water applied to filter media during a backwash.

<h3>Define filtration process. </h3>

Filtration is a physical separation procedure that uses a filter medium with a complicated structure that only allows fluid to pass through it to separate solid particles and liquid from a combination. Filtrate is the term for the liquid that passes through the filter medium and is used to describe solid particles that are too large to pass. Larger-than-average particles have the potential to blind the filter by blocking the filter lattice and forming a filter cake on top of the filter. The term "effective pore size" refers to the size of the biggest particles that may successfully pass through a filter.

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If the area of an iron rod is 10 cm by 0.5 cm and length is 35 cm. Find the value of resistance, if 11x10^-8 ohm.m be the resist

malfutka [58]

Answer:

Resistance of the iron rod, R = 0.000077 ohms

Explanation:

It is given that,

Area of iron rod, $A=10\ cm\times 0.5\ cm=5\ cm^2 = 0.0005\ m^2$

Length of the rod, L = 35 cm = 0.35 m

Resistivity of Iron, $\rho=11\times 10^{-8}\ \Omega-m$

We need to find the resistance of the iron rod. It is given by :

$R=\rho\dfrac{L}{A}$

$R=11\times 10^{-8}\times \dfrac{0.35\ m}{0.0005\ m^2}$

$R=0.000077 \Omega$

So, the resistance of the rod is 0.000077 ohms. Hence, this is the required solution.

6 0

2 years ago

A thin flake of mica (n=1.58) is used to cover one slit of a double-slit interference arrangement. The central point on the wiew

Llana [10]

To develop this problem it is necessary to apply the optical concepts related to the phase difference between two or more materials.

By definition we know that the phase between two light waves that are traveling on different materials (in this case also two) is given by the equation

$\Phi = 2\pi(\frac{L}{\lambda}(n_1-n_2))$

Where

L = Thickness

n = Index of refraction of each material

$\lambda =$ Wavelength

Our values are given as

$\Phi = 7(2\pi)$

$L=t$

$n_1 = 1.58$

$n_2 = 1$

$\lambda = 550nm$

Replacing our values at the previous equation we have

$\Phi = 2\pi(\frac{L}{\lambda}(n_1-n_2))$

$7(2\pi) = 2\pi(\frac{t}{\lambda}(1.58-1))$

$t = \frac{7*550}{1.58-1}$

$t = 6637.931nm \approx 6.64\mu m$

Therefore the thickness of the mica is 6.64μm

3 0

2 years ago

What is parallelogram law of vector addition ???

Vladimir [108]

Answer:

According to the parallelogram law of vector addition if two vectors act along two adjacent sides of a parallelogram(having magnitude equal to the length of the sides) both pointing away from the common vertex, then the resultant is represented by the diagonal of the parallelogram passing through the same common vertex

Explanation:

6 0

2 years ago

Your in an escape room. Only its real and your oxygen runs out in 3 minutes unless you solve this problem, The problem :a ball i

alex41 [277]

The sum of the series allows to find the result for the total distance that the ball bounces is:

total distance = 59.52 in

A series is a set of things or numbers related by a specific operation.

They indicate that the ball falls from an initial height y₀ = 30 in. and it bounces 50% of the height and the process is repeated until it stops, see attached.

Let's build a table to observe the sequence.

drop height rebound

1 30 15

2 15 7.5

3 7.5 3.75

If we call the first term y₀

The first bounce can be found.

y₁ = $\frac{y_o}{2}$

The second bounces.

$y_2 = \frac{y_1}{2} \\y_2 = \frac{y_o}{4}$

The third bounce.

$y_3 = \frac{y_2}{2} \\y_3 = \frac{y_0}{ 8}$

By observing this table we can construct a series of the form

Total distance = $y_o \ ( 1 + \frac{1}{2} + \frac{1}{4}+ \frac{1}{8} + ... +\frac{1}{2n} )$

The sum of the serie has a result of

sum = 127/64 = 1,984

Let's calculate

distance total = 30 1,984

Distance total = 59.52 cm

In conclusion, using the sum of the series we can find the result for the total distance that the ball bounces is:

total distance = 59.52 in

Learn more here: brainly.com/question/8879163

4 0

2 years ago

Read 2 more answers

A 0.335 kg mass is attached to a spring and executes simple harmonic motion with a period of 0.38 s. The total energy of the sys

kramer

Answer:

$k=91.54 \frac{N}{m}$

Explanation:

The angular speed is defined as the angle traveled in one revolution over the time taken to travel it, that is, the period. Therefore, it is given by:

$\omega=\frac{2\pi}{T}\\\omega=\frac{2\pi}{0.38s}\\\omega=16.53\frac{rad}{s}$

The angular frequency of the simple harmonic motion of the mass-spring system is defined as follows:

$\omega=\sqrt{\frac{k}{m}}$

Here, k is the spring's constant and m is the mass of the body attached to the spring. Solving for k:

$\omega^2=\frac{k}{m}\\k=m\omega^2\\k=0.335kg(16.53\frac{rad}{s})^2\\k=91.54 \frac{N}{m}$

6 0

2 years ago