To solve this problem we will use the concepts related to Magnification. Magnification is the process of enlarging the apparent size, not physical size, of something. This enlargement is quantified by a calculated number also called "magnification".
The overall magnification of microscope is
![M = \frac{Nl}{f_ef_0}](https://tex.z-dn.net/?f=M%20%3D%20%5Cfrac%7BNl%7D%7Bf_ef_0%7D)
Where
N = Near point
l = distance between the object lens and eye lens
= Focal length
= Focal of eyepiece
Given that the minimum distance at which the eye is able to focus is about 25cm we have that N = 25cm
Replacing,
![M = \frac{25*10}{3*5}](https://tex.z-dn.net/?f=M%20%3D%20%5Cfrac%7B25%2A10%7D%7B3%2A5%7D)
![M = 16.67\approx 17\\](https://tex.z-dn.net/?f=M%20%3D%2016.67%5Capprox%2017%5C%5C)
Therefore the correct answer is C.
The answer is
Pitch of the buzzer increased (higher tone) as it moves towards the observer
Answer:
A damped oscillation means an oscillation that fades away with time while Forced oscillations occur when an oscillating system is driven by a periodic force that is external to the oscillating system.
Explanation:
Damping is the reduction in amplitude (energy loss from the system) due to overcomings of external forces like friction or air resistance and other resistive forces. ... When a body oscillates by being influenced by an external periodic force, it is called forced oscillation.
<h2>
<em><u>Hope</u></em><em><u> </u></em><em><u>this</u></em><em><u> </u></em><em><u>helped</u></em><em><u> </u></em></h2>
<em><u>Welcome</u></em><em><u> </u></em>
Answer:
12m/s
Explanation:
Given parameters:
Power = 6.5 x 10⁴W
Force = 5.5 x 10³N
Unknown:
The resulting velocity = ?
Solution:
The velocity of a body is related to force and power using the expression below;
Power = Force x velocity
Insert the parameters and solve for velocity
6.5 x 10⁴ = 5.5 x 10³ x velocity
velocity =
= 12m/s
Explanation:
d= 80km = 8000m
t = 45 min = 45/60 h
= 0.75 h
V= ?
we know that,
V = d /t
or,V= 80 km / 0.75 h
- or, V= 106.67 km/hr
or,V= 106.67×1000m / 3600 s
2. or, V= 29.63 m/s