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Sindrei [870]
1 year ago
12

What is the bulk modulus of oxygen if 39.9 g of oxygen occupies 27.9 l and the speed of sound in the oxygen is 342 m/s?

Physics
1 answer:
motikmotik1 year ago
6 0

Bulk modulus of Oxygen is 1.44×10^5 Pa

Given:

mass of Oxygen = 39.9 g

volume of Oxygen = 27.9 l

speed of sound in oxygen = 342 m/s

To Find:

Bulk modulus of Oxygen

Solution:

The density of oxygen gas is

ρ = 0.0399/0.0279 = 1.43 kg/m^3

From v = √B/ρ we find

B = v^2ρ

B = (317 m/s)^2 x (1.43 kg/m^3)

B = 1.44×10^5 Pa

Hence, Bulk modulus of Oxygen is 1.44×10^5 Pa

Learn more about Bulk modulus here:

brainly.com/question/24179667

#SPJ4

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At a distance r1 from a point charge, the magnitude of the electric field created by the charge is 395 N/C. At a distance r2 fro
Ksenya-84 [330]

Answer:

r₂/r₁ = 1.82

Explanation:

The electric field due to a point charge, has the following expression:

E =\frac{k*q}{r^{2}}

For a distance r₁, the magnitude of the electric field is 395 N/C, so we can solve for r₁², as follows:

r₁² = \frac{k*q}{395 N/C} } (1)

For a distance r2, the magnitude of the electric field is 119 N/C, so we can solve for r₂², as follows:

r₂² = \frac{k*q}{119 N/C} }

We can find the quotient r₂/r₁, from (1) and (2):

r₂/r₁ =\sqrt{395/119} = 1.82

7 0
4 years ago
Why does a balloon fully inflated with air rise up vertically for some distance whenpunctured from below?
Virty [35]

Newton's second and third law can be found the correct answer is:

  • The force of the air leaving the balloon by action and reaction causes it to have a positive acceleration upward and rise.

Pressure is defined by the relationship between forces and area,

           P = F / A

Where P is pressure, F is force and A is area

           F = P A

Newton's second law is that the sum of the external forces of a body is proportional to the mass of the body and the acceleration

Newton's third law or action and reaction says that forces in nature appear in pairs on the two interacting bodies, the magnitude of the force is equal, but in the opposite direction; each one is applied to one of the bodies.

A free-body diagram of the process is shown in the attachment

           B + F - W = m a

           W = m g

Where B is the thrust, F the force of air exit, W the weight, m ​​the mass and the acceleration of the body

Archimedes' principle states that the vertical thrust on a body is equal to the fart of the dislodged fluid, in this case air.

            B =ρ_{air} g V_{air}

Where ρ and V_ {air} are the density and volume of the air, respectively,

It's substitute

          ρ_{air} g V_{air} + P A - m g = m a

          a =

The mass of the body is formed by the mass of the balloon plus the mass of air that it contains

Let's analyze this expression in three moments

  • Before opening the hole at the bottom.   The second term is zero, so the thrust is not enough to lift the balloon, the acceleration is negative.
  • Just after opening.  The force of the air coming out that by the law of action and reaction creates a force of equal magnitude and upward direction on the balloon.  The sum of these two forces makes the acceleration positive, therefore the balloon rises
  • After the pressure inside the balloon is equal to the atmospheric pressure.  Tthis case the second term is zero again and the balloon begins to descend with an acceleration less than the acceleration of gravity.

In conclusion with Newton's second and third law we find the correct answer is:

  • The force of the air leaving the balloon by action and reaction law causes it to have a positive acceleration upward and rise.

Learn more about Newton's law here:

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6 0
3 years ago
A parallel-plate capacitor is connected to a battery. What happens to the stored energy if the plate separation is doubled while
zlopas [31]

Answer:

new energy of the capacitor is half that of initial energy

Explanation:

As we know that the energy stored in the capacitor is given as

U = \frac{1}{2}CV^2

here we know that capacitance of parallel plate capacitor is given as

C = \frac{\epsilon_0 A}{d}

V = voltage of battery

so now we have capacitor remains connected to the same battery and the separation between the plates is doubled

so we have

C' = \frac{\epsilon_0 A}{2d}

so now the energy stored between the plates is

U = \frac{1}{2}(\frac{C}{2})V^2

so new energy of the capacitor is half

8 0
4 years ago
The gravitational force between Pluto and Charon is 3.61 × 1018 N. Pluto has a mass of 1.3 × 1022 kg, which is only slightly gre
raketka [301]

<u>Answer:</u>

<em>The distance between Pluto and Charon is  1.96 \times 10^7  m</em>

<u>Explanation:</u>

Force of gravitation between two objects F_g= \frac{G(M_1 M_2 )}{r^2}  

Where M_1  \ and \ M_2  are the masses of the objects,r is the distance between the objects

G is the universal gravitational constant=6.67 \times 10^-^1^1 m^3/kg s^2

Here mass of pluto = 1.3 \times 10^2^2  kg

mass of charon = 1.6 \times 10^2^1 kg

Force of gravitation F_g=3.61 \times 10^1^8  N

F_g= \frac {G(M_1 M_2 )}{r^2}

r^2= \frac {G(M_1 M_2 )}{F_g }

r= \sqrt \frac{(G(M_1 M_2 )}{F_g}

=\sqrt \frac {((6.674\times 10^-^1^1) \times 1.3 \times 10^2^2 \times 1.6\times 10^2^1)}{(3.61 \times 10^1^8 )}

=\sqrt \frac {(13.88*10^32)}{(3.61*10^18)}

=1.96 \times10^7  m

4 0
4 years ago
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