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Stolb23 [73]
2 years ago
13

Why does a balloon fully inflated with air rise up vertically for some distance whenpunctured from below?

Physics
1 answer:
Virty [35]2 years ago
6 0

Newton's second and third law can be found the correct answer is:

  • The force of the air leaving the balloon by action and reaction causes it to have a positive acceleration upward and rise.

Pressure is defined by the relationship between forces and area,

           P = F / A

Where P is pressure, F is force and A is area

           F = P A

Newton's second law is that the sum of the external forces of a body is proportional to the mass of the body and the acceleration

Newton's third law or action and reaction says that forces in nature appear in pairs on the two interacting bodies, the magnitude of the force is equal, but in the opposite direction; each one is applied to one of the bodies.

A free-body diagram of the process is shown in the attachment

           B + F - W = m a

           W = m g

Where B is the thrust, F the force of air exit, W the weight, m ​​the mass and the acceleration of the body

Archimedes' principle states that the vertical thrust on a body is equal to the fart of the dislodged fluid, in this case air.

            B =ρ_{air} g V_{air}

Where ρ and V_ {air} are the density and volume of the air, respectively,

It's substitute

          ρ_{air} g V_{air} + P A - m g = m a

          a =

The mass of the body is formed by the mass of the balloon plus the mass of air that it contains

Let's analyze this expression in three moments

  • Before opening the hole at the bottom.   The second term is zero, so the thrust is not enough to lift the balloon, the acceleration is negative.
  • Just after opening.  The force of the air coming out that by the law of action and reaction creates a force of equal magnitude and upward direction on the balloon.  The sum of these two forces makes the acceleration positive, therefore the balloon rises
  • After the pressure inside the balloon is equal to the atmospheric pressure.  Tthis case the second term is zero again and the balloon begins to descend with an acceleration less than the acceleration of gravity.

In conclusion with Newton's second and third law we find the correct answer is:

  • The force of the air leaving the balloon by action and reaction law causes it to have a positive acceleration upward and rise.

Learn more about Newton's law here:

brainly.com/question/13959891

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A swimmer bounces almost straight up from a diving board and falls vertically feet first into a pool.she starts with a speed of
garik1379 [7]

Answer:

a) 1.20227 seconds

b) 0.98674 m

c) 7.3942875 m/s

Explanation:

t = Time taken

u = Initial velocity = 4.4 m/s

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 9.81 m/s²

v=u+at\\\Rightarrow 0=4.4-9.81\times t\\\Rightarrow \frac{-4.4}{-9.81}=t\\\Rightarrow t=0.44852\ s

s=ut+\frac{1}{2}at^2\\\Rightarrow s=4.4\times 0.44852+\frac{1}{2}\times -9.81\times 0.44852^2\\\Rightarrow s=0.98674\ m

b) Her highest height above the board is 0.98674 m

Total height she would fall is 0.98674+1.8 = 2.78674 m

s=ut+\frac{1}{2}at^2\\\Rightarrow 2.78674=0t+\frac{1}{2}\times 9.81\times t^2\\\Rightarrow t=\sqrt{\frac{2.78674\times 2}{9.81}}\\\Rightarrow t=0.75375\ s

a) Her feet are in the air for 0.75375+0.44852 = 1.20227 seconds

v=u+at\\\Rightarrow v=0+9.81\times 0.75375\\\Rightarrow v=7.3942875\ m/s

c) Her velocity when her feet hit the water is 7.3942875 m/s

3 0
3 years ago
An airplane flying at an altitude of 6 miles passes directly over a radar antenna. When the airplane is 10 miles away (s = 10),
Novosadov [1.4K]

Answer:

Explanation:

Given

altitude of the Plane h=6\ miles

When Airplane is s=10\ miles away

Distance is changing at the rate of \frac{\mathrm{d} s}{\mathrm{d} t}=290\ mph

From diagram we can write as

h^2+x^2=s^2

differentiate above equation w.r.t time

2h\frac{\mathrm{d} h}{\mathrm{d} t}+2x\frac{\mathrm{d} x}{\mathrm{d} t}=2s\frac{\mathrm{d} s}{\mathrm{d} t}

as altitude is not changing therefore \frac{\mathrm{d} h}{\mathrm{d} t}=0

0+x\frac{\mathrm{d} x}{\mathrm{d} t}=s\frac{\mathrm{d} s}{\mathrm{d} t}

at s=10\ miles\ and\ h=6\ miles

substitute the value we get x=\sqrt{10^2-6^2}=8\ miles

8\times \frac{\mathrm{d} x}{\mathrm{d} t}=10\times 290

\frac{\mathrm{d} x}{\mathrm{d} t}=362.5\ mph

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A box experiencing a gravitational force of 600 N is being pulled to the right with force of 250 N. A 25 N frictional force acts
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The answer is: 0 Newtons
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How much time will it take for a coyote to travel 48 meters across the field to get to the unsuspecting rabbit eating grass in t
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Formula for time
t=d/s
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t=12s
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