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Stolb23 [73]
2 years ago
13

Why does a balloon fully inflated with air rise up vertically for some distance whenpunctured from below?

Physics
1 answer:
Virty [35]2 years ago
6 0

Newton's second and third law can be found the correct answer is:

  • The force of the air leaving the balloon by action and reaction causes it to have a positive acceleration upward and rise.

Pressure is defined by the relationship between forces and area,

           P = F / A

Where P is pressure, F is force and A is area

           F = P A

Newton's second law is that the sum of the external forces of a body is proportional to the mass of the body and the acceleration

Newton's third law or action and reaction says that forces in nature appear in pairs on the two interacting bodies, the magnitude of the force is equal, but in the opposite direction; each one is applied to one of the bodies.

A free-body diagram of the process is shown in the attachment

           B + F - W = m a

           W = m g

Where B is the thrust, F the force of air exit, W the weight, m ​​the mass and the acceleration of the body

Archimedes' principle states that the vertical thrust on a body is equal to the fart of the dislodged fluid, in this case air.

            B =ρ_{air} g V_{air}

Where ρ and V_ {air} are the density and volume of the air, respectively,

It's substitute

          ρ_{air} g V_{air} + P A - m g = m a

          a =

The mass of the body is formed by the mass of the balloon plus the mass of air that it contains

Let's analyze this expression in three moments

  • Before opening the hole at the bottom.   The second term is zero, so the thrust is not enough to lift the balloon, the acceleration is negative.
  • Just after opening.  The force of the air coming out that by the law of action and reaction creates a force of equal magnitude and upward direction on the balloon.  The sum of these two forces makes the acceleration positive, therefore the balloon rises
  • After the pressure inside the balloon is equal to the atmospheric pressure.  Tthis case the second term is zero again and the balloon begins to descend with an acceleration less than the acceleration of gravity.

In conclusion with Newton's second and third law we find the correct answer is:

  • The force of the air leaving the balloon by action and reaction law causes it to have a positive acceleration upward and rise.

Learn more about Newton's law here:

brainly.com/question/13959891

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Two identical mandolin strings under 200 N of tension are sounding tones with frequencies of 590 Hz. The peg of one string slips
Slav-nsk [51]

To solve this problem it is necessary to apply the concepts related to frequency and vibration of strings. Mathematically the frequency can be expressed as

f = \frac{v}{\lambda}

Then the relation between two different frequencies with same wavelength would be

\frac{f'}{f} = \frac{v'/\wavelength}{v/\wavelength}

\frac{f'}{f} = \frac{v'}{v}

The beat frequency heard when the two strings are sounded simultaneously is

f_{beat} = f-f'

f_{beat} = f(1-\frac{f'}{f})

f_{beat} = f(1-\frac{v'}{v})

We have the velocity of the transverse waves in stretched string as

v = \sqrt{\frac{T}{\mu}}

v = \sqrt{\frac{200N}{\mu}}

And,

v' = \sqrt{\frac{196N}{\mu}}

Therefore the relation between the two is,

\frac{v'}{v} = \sqrt{\frac{192}{200}}

\frac{v'}{v} = \sqrt{0.96}

Finally substituting this value at the frequency beat equation we have

f_{beat} = 590(1-\sqrt{0-96})

f_{beat} = 11.92Hz

Therefore the beats per second are 11.92Hz

4 0
3 years ago
Given f(x)=3x-11 which of the following is f(7)<br><br> A. 10<br> B. 32<br> C. -6<br> D. 6
Crazy boy [7]

Answer:

The answer is A. 10

Explanation:

<em>Given </em>

<em>f(</em><em>x</em><em>)</em><em> </em><em>=</em><em> </em><em>3x </em><em>-</em><em> </em><em>1</em><em>1</em>

<em>So, </em><em> </em>

<em>f(</em><em>7</em><em>)</em><em> </em><em>=</em><em> </em><em>3</em><em> </em><em>*</em><em> </em><em>7</em><em> </em><em>-</em><em> </em><em>1</em><em>1</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em> </em><em>2</em><em>1</em><em> </em><em>-</em><em> </em><em>1</em><em>1</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em> </em><em>1</em><em>0</em>

5 0
3 years ago
Read 2 more answers
A ball rolls from x = - 5m to x = 0m in 1 second . What was its average velocity? (Units = m/s) Don't forget: velocities and dis
katrin2010 [14]

Answer:

+ 5 m/s

Explanation:

change in displacement = ΔX=final position - initial position

                                            ΔX = 0-(-5) =0+5 =+ 5 m

average velocity =  ΔX/t

                             = +5/1

                             = + 5 m/s

positive sign shows that ball rolls towards right

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guajiro [1.7K]

The square root of 80 is: 8.944

3 0
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If a cliff jumper leaps off the edge of a 100m cliff, how long does she fall before hitting the water? (assume zero air resistan
andrew-mc [135]
<h2>Answer:</h2>

<em>Hello, </em>

<h3><u>QUESTION)</u></h3>

Assuming that the initial velocity of the jumper is zero, on Earth any freely falling object has an acceleration of 9.8 m/s².  

<em>✔ We have : a = v/Δt = ⇔ Δt = v/a </em>

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  • Δt ≈ 4,5 s

4 0
3 years ago
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