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taurus [48]
3 years ago
12

1 liter= 10 cubic centimeters?

Physics
1 answer:
Katena32 [7]3 years ago
7 0
No. It's equal to 1,000 of them.
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How do you find out the missing masses in a balloon
Mamont248 [21]

Answer:

How do you find out the missing masses in a balloon?

Well, actually you can't find the missing masses in a balloon. Why?

Because the mass of the mass of balloon, it can't see the mass of it, it only see if it the balloon is deflated or inflated.

Explanation:

Hope it helps

#LetsStudy

7 0
3 years ago
How old is a bone if it still has 50% of its carbon-14 content?
Degger [83]

Answer:

5730 years

Explanation:

The half life of carbon-14 is 5730 years.  If 50% of the carbon-14 remains, then exactly 1 half life has passed.

The half-life equation is:

A = A₀ (½)^(t / T)

where A is the remaining amount,

A₀ is the initial amount,

t is time,

and T is the half life.

In this case, A = ½ A₀ and T = 5730.

½ A₀ = A₀ (½)^(t / 5730)

½ = (½)^(t / 5730)

1 = t / 5730

t = 5730

6 0
2 years ago
At an instant when the displacement is equal to a/2, what fraction of the total energy of the system is potential?
madreJ [45]
<span>At an instant when the displacement is equal to a/2, Potential energy U = 1/2ka(square) where a is displacement. when a= a/2 U = 1/4ka(square) U = E/4 Potential Energy = 1/4 Total energy</span>
4 0
3 years ago
Two identical cylindrical vessels with their bases at the same level each contain a liquid of density 1.23 g/cm3. The area of ea
motikmotik

Explanation:

Work done by gravity is given by the formula,

           W = \rho A (h_{1} - h)g (h - h_{2}) ......... (1)

It is known that when levels are same then height of the liquid is as follows.

           h = \frac{h_{1} + h_{2}}{2} ......... (2)

Putting value of equation (2) in equation (1) the overall formula will be as follows.

       W = \frac{1}{4} \rho gA(h_{1} - h_{2})^{2})

           = \frac{1}{4} \times 1.23 g/cm^{3} \times 9.80 m/s^{2} \times 3.89 \times 10^{-4} m^{2}(1.76 m - 0.993 m)^{2})

           = 0.689 J

Thus, we can conclude that the work done by the gravitational force in equalizing the levels when the two vessels are connected is 0.689 J.

3 0
3 years ago
Point charge q1 of 30 nC is separated by 50 cm from point charge q2 of -45 nC. As shown in the diagram, point a is located 30 cm
Angelina_Jolie [31]

Answer:

E1 =  2996.667N/C E2 = 11237.5N/C

Explanation:

E1 = kQ1/r^2

  =8.99 x 10^9 x 30 x 10^-9/(30x10^-2)^2

  = 2996.667N/C

E2 = kQ2/r^2

      = 8.99 x 10^9 x 50 x 10^-9/(20x10^-2)^2

      = 11237.5N/C

The direction are towards the point a

6 0
3 years ago
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