The problem is missing some parts but nevertheless here is
the answer:
Given:
1.7 m long barbell with 23 kg weight on the left and 34 in
the right end.
Solution:
Calculating from the left side:
Center of gravity = ΣM/ΣW = [23*0 + 9*(1.7/2) + 34*1.7]/[23+9+34]
Center of gravity = .992 m from the left end
We use the Planck’s formula:
E = hv
where,
E = energy, h = planck’s constant = 6.6x10^-34 J s, v =
frequency in Hz (Hz = 1 / s)
Subsituting the values to find for E:
E = (6.6×10^-34 J s) * 9.85×10^14 / s
E = 6.5x10^-19 J
Answer:
8
Explanation:
Finding time= t=change in velocity or distance/acceleration
so 32/9.5-5.5
32/4
8
The gravitational pull on moon A will be lower since it is further away from the new planet.
