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1 year ago

There is a container on the lab bench containing some unknown chemical. what should you do?

1 answer:

6 0

Ask your lab manager for instructions. If you happen to be the lab manager, take out the container (making a note of where it is), find the culprit, and try to figure out what might be in the beaker so you can know how to properly dispose of it.

Proper safety measures should be followed.

<h2>What are the safety measures in chemistry lab?</h2>

In the lab, always use the proper eye protection, such as chemical splash goggles. When handling hazardous items, put on the disposable gloves that the laboratory has given. Before leaving the lab, take the gloves off. Put on a full-length, long-sleeved lab coat (apron) or apron that can withstand chemicals.

To know more about Safety measures, go to the URL

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A man heats a balloon in the oven. If the balloon initially has a volume of 0.4 liters and a temperature of 20 degrees celsius,

Airida [17]

Answer:

0.714 liter.

Explanation:

Given:

The balloon initially has a volume of 0.4 liters and a temperature of 20 degrees Celsius.

It is heated to a temperature of 250 degrees Celsius.

Question asked:

What will be the volume of the balloon after he heats it to a temperature of 250 degrees Celsius ?

Solution:

By using:

$PV=nRT$

Assuming pressure as constant,

V∝ T

Now, let K is the constant.

V = KT

Let initial volume of balloon , $V_{1}$ = 0.4 liter

1000 liter = 1 meter cube

1 liter = $\frac{1}{1000} m^{3} = 10^{-3} m^{3$

0.4 liter = $0.4\times10^{-3}=4\times10^{-4} m^{3}$

And initial temperature of balloon, $T_{1}$ = 20°C = (273 + 20)K

= 293 K

Let the final volume of balloon is $V_{2}$

And a given, final temperature of balloon, $T_{2}$ is 250°C = (273 + 250)K

= 523 K

Now, $V_{1}$ = $KT_{1}$

$4\times10^{-4}=K\times293\ (equation\ 1 )$

$V_{2}$ = $KT_{2}$

$=K\times523\ (equation 2)$

Dividing equation 1 and 2,

$\frac{4\times10^{-4}}{V_{2} } =\frac{K\times293}{K\times523}$

K cancelled by K.

By cross multiplication:

$293V_{2} =4\times10^{-4} \times523\\V_{2} =\frac{ 4\times10^{-4} \times523\\}{293} \\ = \frac{2092\times10^{-4}}{293} \\ =7.14\times10^{-4}m^{3}$

Now convert it into liter with the help of calculation done above.

$7.14\times10^{-4} \times1000\\7.14\times10^{-4} \times10^{3} \\0.714\ liter$

Therefore, the volume of the balloon be after he heats it to a temperature of 250 degrees Celsius is 0.714 liter.

5 0

2 years ago

Select 2-possible ointment bases. Select one or more:

fredd [130]

Answer:

The correct option is: c. petroleum jelly, d. Polyethylene glycol 4000/600 mixture

Explanation:

Topical medications are used for the treatment of ailments and include ointments, gels, lotions creams etc. that can applied directly on the surface of the body i.e. skin.

An ointment base medication gets rapidly absorbed into the skin. Some of the examples of <u>ointment bases</u> include water-soluble bases: <u>polyethylene glycol</u>, hydrocarbon bases: <u>petroleum jelly</u>, paraffin wax.

7 0

2 years ago

Plz help hurry! I will give brainlest

Ede4ka [16]

Answer: mitochondria

Explanation:

it affects the cell because it produces the power of the cell, let me know if this helpes

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2 years ago

What is the partial pressure of carbon dioxide in a container that contains 3.63 mol of oxygen, 1.49 mol of nitrogen, and 4.49 m

lana66690 [7]

Answer: