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Free_Kalibri [48]
3 years ago
13

Write the name of the element that corresponds to each of the following symbols.

Chemistry
2 answers:
Fed [463]3 years ago
8 0
Kr= krypton
K= potassium
C=carbon
En= neon
Si= silicon
Au= gold
Ni= nitrogen
Br= berillium
Mg=magnesium
Mn= mangenese
Al: aluminum
ivolga24 [154]3 years ago
8 0
Kr= Krypton
K= potassium
C= carbon
Ne= neon
Si= silicon
Zr = zirconium
Sn= tin
Pt = platinum
Na = sodium
Al= aluminium
P = phosphorus
Cu= copper
Ag = silver
Mn= manganese
Au= gold
Mg = magnesium
Ni = nickel
Br = Bromine
Hg =Mercury
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At a certain temperature, 0.900 mol SO 3 is placed in a 2.00 L container. 2 SO 3 ( g ) − ⇀ ↽ − 2 SO 2 ( g ) + O 2 ( g ) At equil
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Answer: The value of K_c is 0.0057

Explanation:

Initial moles of  SO_3 = 0.900 mole

Volume of container = 2.00 L

Initial concentration of SO_3=\frac{moles}{volume}=\frac{0.900moles}{2.00L}=0.450M  

equilibrium concentration of O_2=\frac{moles}{volume}=\frac{0.110mole}{2.00L}=0.055M [/tex]

The given balanced equilibrium reaction is,

                            2SO_3(g)\rightleftharpoons 2SO_2(g)+O_2(g)

Initial conc.              0.450 M               0        0

At eqm. conc.    (0.450 -2x) M         (2x) M   (x) M

The expression for equilibrium constant for this reaction will be,

K_c=\frac{[O_2][SO_2]^2}{[SO_3]^2}

K_c=\frac{x\times (2x)^2}{0.450-2x)^2}

we are given : x = 0.055

Now put all the given values in this expression, we get :

K_c=\frac{0.055\times (2\times 0.055)^2}{0.450-2\times 0.055)^2}

K_c=0.0057

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Explanation:

  • When nucleotides polymerize to form nucleic acids, the hydroxyl group attached to the 3′ carbon of a sugar of one nucleotide forms an ester bond to the phosphate of another nucleotide, eliminating a molecule of water.

Summary:

So the phosphate group of one nucleotide form bond with the hydroxyl group of an other nucleotide with the elimination of water molecules.

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