All categories

2 years ago

The formula for change in momentum?

Physics

1 answer:

goblinko [34]2 years ago

6 0

Answer:

<h2><em><u>Momentum is the product of the mass and velocity of an object and describes mass in motion. Impulse: Impulse is a force that is applied to cause a change in momentum. The change in momentum of an object, Δp=m(vf−vi) Δ p = m ( v f − v i ) is equal to the impulse, J </u></em></h2>

You might be interested in

The work done in holding a 30kg of bricks to a height of 20m is

ella [17]

The work done to "HOLD" a load of bricks at any height is zero.
Work is done only when force acts through a DISTANCE.

The work done to LIFT 30 kg of anything to 20m higher than
it already is, is

(force) · (vertical distance)

= (mass) · (gravity) · (vertical distance)

= (30 kg) · (9.8 m/s²) · (20 m)

= 5,880 joules

8 0

3 years ago

A large heavy truck smashes into a brick wall totally crumpling the front end. what is the conclusion of this description

Oduvanchick [21]

The person driving the truck was killed
the wall was destroyed

8 0

3 years ago

A parallel-plate, air-gap capacitor has a capacitance of 0.14 mu F. The plates are 0.5 mm apart, What is the area of each plate?

Marysya12 [62]

Answer:

7.9060 m²

8.57 Volts

5.142×10⁻⁶ Joule

1.2×10⁻⁶ Coulomb

Explanation:

C = Capacitance between plates = 0.14 μF = 0.14×10⁻⁶ F

d = Distance between plates = 0.5 mm = 0.5×10⁻³ m

Q = Charge = 1.2 μC = 1.2×10⁻⁶ C

ε₀ = Permittivity = 8.854×10⁻¹² F/m

Capacitance

$C=\frac{\epsilon_{0}A}{d}\\\Rightarrow A=\frac{Cd}{\epsilon_{0}}\\\Rightarrow A=\frac{0.14\times 10^{-6}\times 0.5\times 10^{-3}}{8.854\times 10^{-12}}\\\Rightarrow A=7.9060\ m^2$

∴ Area of each plate is 7.9060 m²

Voltage

$V=\frac{Q}{C}\\\Rightarrow V=\frac{1.2\times 10^{-6}}{0.14\times 10^{-6}}\\\Rightarrow V=8.57\ Volts$

∴ Potential difference between the plates if the capacitor is charged to 1.2 μC is 8.57 Volts.

Energy stored

E=0.5CV²

⇒E = 0.5×0.14×10⁻⁶×8.57²

⇒E = 5.142×10⁻⁶ Joule

∴ Stored energy is 5.142×10⁻⁶ Joule

Charge

Q = CV

⇒Q = 0.14×10⁻⁶×8.57

⇒Q = 1.2×10⁻⁶ C

∴ Charge the capacitor carries before a spark occurs between the two plates is 1.2×10⁻⁶ Coulomb

6 0

3 years ago

The 2-Mg truck is traveling at 15 m/s when the brakes on all its wheels are applied, causing it to skid for 10 m before coming t

Scorpion4ik [409]

Answer:

constant horizontal force developed in the coupling C = 11.25KN

the friction force developed between the tires of the truck and the road during this time is 33.75KN

Explanation:

See attached file

8 0

4 years ago

Consider a perfectly reflecting mirror oriented so that solar radiation of intensity I is incident upon, and perpendicular to, t

VLD [36.1K]

Answer:

Frad = 2IA/C

Explanation:

see attached file

4 0

3 years ago