There can be two cases
Case 1:
When a molecule has one carbon-carbon double bond and four monovalent atoms or groups in which two atoms on same carbon are different, there will be 2 isomers, one cis and one trans.
Case 2:
When a molecule has one carbon-carbon double bond and four monovalent atoms or groups where both atoms attached to the same carbon are same, there will be no geometrical isomerism.
As based on priority, there will be only two orientations possible , in which same priority atoms are on the same side that is cis and if they are on the opposite side that is trans.
I got this idk if it's correct: For measuring large distances, the kilometer (103 or 1000 meters) is often used. The basic unit of volume in the metric system is the liter (l). The most common derived unit is the milliliter (ml) (10-3 or 1/1000 of a liter). The volume of a milliliter is equal to the volume of a cube 1 centimeter per side.
Step 1 - Since 3.3mm^3 = 0.0033cm^3, convert that to 3.3x10^-3 cm^3.
Step 2 - Since 1cm^3 = 1x10^-6 m^3, times 3.3 by that. (3.3 x 1 x 10^-6) = 0.0000033
Step 3 - 0.0000033 = 3.3 x 10 ^-6 m^3, which is your answer choice A.
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The phosphorylation of fructose 6-phosphate to fructose-1,6-bisphosphate is the committed step in glycolysis because. it is the rate-limiting step
<h3>What is
phosphorylation?</h3>
The first step in the metabolism of carbohydrates is frequently their phosphorylation. Because the phosphate group stops the molecules from migrating back across the transporter, phosphorylation enables cells to store carbohydrates. Glucose phosphorylation is a crucial step in the metabolism of sugar. In the first phase of glycolysis, D-glucose is converted to D-glucose-6-phosphate using the chemical equation D-glucose + ATP D-glucose-6-phosphate + ADP G° = 16.7 kJ/mol (° signifies measurement under standard conditions).
The rate-limiting stage in the liver's metabolism of glucose is the initial rate of phosphorylation of glucose (ATP-D-glucose 6-phosphotransferase) and non-specific hexokinase. Hepatic cells are freely permeable to glucose (ATP-D-hexose 6-phosphotransferase).
encouraging certain glucose transporters to translocate to the cell membrane.
To learn more about phosphorylation from the given link:
brainly.com/question/2138188
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