Answer:
39.2 g
Explanation:
- 2Ni₂O₃(s) ⟶ 4Ni(s) + 3O₂(g)
First we <u>convert 55.3 grams of Ni₂O₃ into moles of Ni₂O₃</u>, using its<em> molar mass</em>:
- 55.3 g ÷ 165.39 g/mol = 0.334 mol Ni₂O₃
Then we <u>convert 0.334 moles of Ni₂O₃ into moles of Ni</u>, using the <em>stoichiometric coefficients of the balanced reaction</em>:
- 0.334 mol Ni₂O₃ *
= 0.668 mol Ni
Finally we <u>calculate how much do 0.668 Ni moles weigh</u>, using the<em> molar mass of Ni </em>:
- 0.668 mol Ni * 58.69 g/mol = 39.2 g
The given reaction equation for photosynthesis whereby, in the presence of light energy from the Sun and chlorophyll, plants synthesize glucose from carbon dioxide and water. As water is present as a reactant, it doesn’t also appear on the ’products’ side of the equation. So:
Water + carbon dioxide > glucose + oxygen.
As glucose contains 6 carbon atoms, these must be obtained from 6 molecules of CO2. So, overall:
6CO2(g) + 6H2O(l) > C6H12O6(aq) + 6O2(g).
What is photosynthesis?
Photosynthesis is the process plants and other organisms use to convert light energy into chemical energy, which is later released through cellular respiration to power the activity of the organism.
Therefore, This is the equation for photosynthesis whereby, in the presence of light energy from the Sun and chlorophyll, plants synthesize glucose from carbon dioxide and water.
To learn more about photosynthesis refer the given link:-
brainly.com/question/26071939
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Explanation:
option option B is the correct answer of given statement helium-4(He)=2
Answer:
1 .
2.
Explanation:
The more stable the ionic compound, the more is it lattice energy.
- The more the charge on the cation and the anion, the greater is the lattice energy.
- The less the size of the cation and the anion, the greater is the lattice energy.
Scandium oxide (
) is an oxide in which
behaves as cation and
behaves as anion.
The compounds which has higher lattice energy than scandium oxide are:
1 .
This is because the charge are same on the cation and the anion as in the case of the Scandium oxide but the size of the cation
is smaller than
. Thus, this corresponds to higher lattice energy.
2.
This is because the charge on the cation
is greater than that of
and also the size of the cation
is smaller than
. Thus, this corresponds to higher lattice energy.