Question

In the Haber process, 30.00 g of nitrogen gas is combined with 30.00 g of hydrogen gas to form ammonia gas, NH3. What mass, in grams, of ammonia will form?

Answer 1

Answer:

Mass = 36.38 g

Explanation:

Given data:

Mass of hydrogen = 30.0 g

Mass of nitrogen = 30.0 g

Theoretical yield of reaction = ?

Mass of ammonia = ?

Chemical equation:

N₂+ 3H₂  → 2NH₃

Number of moles of N₂:

Number of moles  = Mass /molar mass

Number of moles = 30 g / 28 g/mol

Number of moles = 1.07 mol

Number of moles of H₂:

Number of moles = Mass /molar mass

Number of moles = 30 g / 2g/mol

Number of moles = 15 mol

Now we will compare the moles of NH₃ with hydrogen and nitrogen .

                 H₂             :                 NH₃

                 3               :                 2

                15              :                2/3×15= 10 mol

                 N₂             :                 NH₃

                 1                :                  2

               1.07             :               2 × 1.07= 2.14 mol

The number of moles of NH₃ produced by nitrogen are less it will be limiting reactant.

Mass of ammonia:

Mass of NH₃  = moles × molar mass

Mass =2.14 mol × 17 g/mol

Mass = 36.38 g