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KatRina [158]
4 years ago
6

How many grams are in 5.66 mol of caco3?

Chemistry
2 answers:
mr_godi [17]4 years ago
6 0
To calculate the mass of a given number of moles of a substance, it is important to determine the molar mass of the substance. For CaCO3, the molar mass is equal to 100.09 g / mol. We calculate as follows:

5.66 mol CaCO3 ( 100.09 g / mol ) = 566.51 grams of CaCO3
nalin [4]4 years ago
3 0

When you have a substance made of some molecules you need to know each mass, in this case, CaCO3 has one atom of Ca, one atom of C and three of O.

Ca: 40.078 grams per mol

C: 12.011 grams per mol

O: 15.999 gramps per mol

[Ca+C+(O*3)]= 1 mol

[40.078 + 12.011 + (3*15.999)]=100.086 grams per mol

Now, they ask you about 5.66 moles. You could do a cross multiplication and say:

1mol-------100.086 grams

5.66mol----X= 566,48676 grams = 566,5 grams

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Given:
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Answer:

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Explanation:

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CaC₂ + N₂ → CaCN₂ + C.

  • It is clear that 1.0 mole of CaC₂ reacts with 1.0 mole of N₂ to produce 1.0 mole of CaCN₂ and 1.0 mole of C.
  • We need to calculate the no. of moles of 265.0 g of CaCN₂ produced using the relation:

n = mass / molar mass = (265.0 g) / (80.102 g/mol) = 3.308 mol.

  • We should get the no. of moles of N₂ needed to produce 3.308 mol of CaCN₂.

∵ 1.0 mole of N₂ produces → 1.0 mole of CaCN₂.

<em>∴ 3.308 mole of N₂ produces → 3.308 mole of CaCN₂.</em>

  • Now, we can get the grams of N₂  consumed to produce 265.0 g of CaCN₂:

∴ The grams of N₂ = n x molar mass = (3.308 mole)(28.0 g/mol) = 92.63 g = 92.6 g.

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