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KatRina [158]
3 years ago
6

How many grams are in 5.66 mol of caco3?

Chemistry
2 answers:
mr_godi [17]3 years ago
6 0
To calculate the mass of a given number of moles of a substance, it is important to determine the molar mass of the substance. For CaCO3, the molar mass is equal to 100.09 g / mol. We calculate as follows:

5.66 mol CaCO3 ( 100.09 g / mol ) = 566.51 grams of CaCO3
nalin [4]3 years ago
3 0

When you have a substance made of some molecules you need to know each mass, in this case, CaCO3 has one atom of Ca, one atom of C and three of O.

Ca: 40.078 grams per mol

C: 12.011 grams per mol

O: 15.999 gramps per mol

[Ca+C+(O*3)]= 1 mol

[40.078 + 12.011 + (3*15.999)]=100.086 grams per mol

Now, they ask you about 5.66 moles. You could do a cross multiplication and say:

1mol-------100.086 grams

5.66mol----X= 566,48676 grams = 566,5 grams

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a chemist adds of a calcium bromide solution to a reaction flask. calculate the mass in grams of calcium bromide the chemist has
mestny [16]

The mass of Calcium bromide added in the flask is 29.7 g.

<h3>What is Molarity? </h3>

Molarity is defined as the ratio of number of moles od solute to the number of volume of solution in litres.

Molarity = number of moles/ volume

<h3>Calculation of Moles</h3>

Number of moles = Molarity × volume

Given,

Molarity of Calcium bromide = 0.363 M

Volume of Calcium bromide = 410 mL

= 0.410L

By substituting all the value, we get

Number of moles = 0.363 × 0.410

= 0.148 mol

As we know that,

Molar mass of Calcium bromide = 199.89 g

<h3>What is Mole? </h3>

Mole is defined as the given mass of substance to the molar mass of substance.

Given mass = Moles × Molar mass

= 0.148 × 199.89

= 29.75 g

= 29.7 g (significant digit)

Thus, we calculated that the mass of Calcium bromide added in the flask is 29.7 g.

learn more about Molarity:

brainly.com/question/19517011

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DISCLAIMER:

The above question is incomplete. Below is the complete question

A chemist adds 410.0mL of a 0.363 M calcium bromide solution to a reaction flask. calculate the mass in grams of calcium bromide the chemist has added to the flask. round your answer to 3 significant digits.

4 0
2 years ago
How many grams of sucrose (c12h22o11) are in 1.55 l of 0.758 m sucrose solution? express your answer in grams to three significa
satela [25.4K]
The molecular formula of sucrose is - C₁₂H₂₂O₁₁
molecular mass of sucrose - 342 g/mol
molarity of sucrose solution is 0.758 M
In 1 L solution the number of sucrose moles are - 0.758 mol
Therefore in 1.55 L solution, sucrose moles are - 0.758 mol/L x 1.55 L
                                                                           = 1.17 mol
The mass of 1.17 mol of sucrose is - 1.17 mol x 342 g/mol = 4.00 x 10² g

7 0
3 years ago
Read 2 more answers
The balanced chemical equation for the complete combustion propane, C3H8 is: C3H8 + 5O2 → 3CO2 + 4 H2O How many moles of H2O wou
BartSMP [9]
4/5 × 0.200 moles= 0.160moles
8 0
3 years ago
What is the limiting reactant when 4 mol P4 and 4 mol S8 react.
In-s [12.5K]

Taking into account the reaction stoichiometry, P₄ will be the limiting reagent.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

8 P₄ + 3 S₈ → 8 P₄S₃

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • P₄: 8 moles
  • S₈: 3 moles
  • P₄S₃: 8 moles

<h3>Limiting reagent</h3>

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

<h3>Limiting reagent in this case</h3>

To determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 3 moles of S₈ reacts with 8 moles of P₄, 4 moles of S₈ reacts with how many moles of P₄?

moles of P_{4} =\frac{4 moles of S_{8} x8 moles of P_{4} }{3 moles of S_{8}}

<u><em>moles of P₄= 10.667 moles</em></u>

But 10.667 moles of P₄ are not available, 4 moles are available. Since you have less amount of moles than you need to react with 4 moles of S₈, P₄ will be the limiting reagent.

Learn more about the reaction stoichiometry:

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6 0
2 years ago
1.In the outline find your section on soil horizons. In it you will find a diagram representing a view of a soil cut away. Which
gogolik [260]
What grade level 
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3 0
3 years ago
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