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KatRina [158]
4 years ago
6

How many grams are in 5.66 mol of caco3?

Chemistry
2 answers:
mr_godi [17]4 years ago
6 0
To calculate the mass of a given number of moles of a substance, it is important to determine the molar mass of the substance. For CaCO3, the molar mass is equal to 100.09 g / mol. We calculate as follows:

5.66 mol CaCO3 ( 100.09 g / mol ) = 566.51 grams of CaCO3
nalin [4]4 years ago
3 0

When you have a substance made of some molecules you need to know each mass, in this case, CaCO3 has one atom of Ca, one atom of C and three of O.

Ca: 40.078 grams per mol

C: 12.011 grams per mol

O: 15.999 gramps per mol

[Ca+C+(O*3)]= 1 mol

[40.078 + 12.011 + (3*15.999)]=100.086 grams per mol

Now, they ask you about 5.66 moles. You could do a cross multiplication and say:

1mol-------100.086 grams

5.66mol----X= 566,48676 grams = 566,5 grams

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What are the controlled variables for water of crystallization experiment?
yarga [219]

Given what we know, we can confirm that as with any experiment, the control variable will be the one that through each trial of the experiment, no matter how many times it is performed, stays constant.

<h3>What is a controlled variable?</h3>
  • A variable that remains constant through an experiment.
  • They are used to compare results to the normal condition.
  • They are also used to isolate the changes to one factor at a time and thus know its exact effects on the outcome.
  • This increases the accuracy of the data and the subsequent conclusion.

Therefore, we can confirm that if a variable stays constant through each phase and trial of an experiment, it is considered to be a controlled variable and is useful in order to increase the accuracy of the conclusion.

To learn more about control variables visit:

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7 0
3 years ago
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kolbaska11 [484]

Answer:

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Explanation:

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5 0
3 years ago
A 10.21 mol sample of argon gas is maintained in a 0.7564 L container at 296.9 K. What is the pressure in atm calculated using t
soldi70 [24.7K]

Answer:

The pressure in atm calculated using the van der Waals' equation, is 337.2atm

Explanation:

This is the Van der Waals equation for real gases:

(P + a/v² ) ( v-b) = R .T

where P is pressure

v is Volume/mol

R is the gas constant and T, T° in K

a y b are constant for each gas, so those values are data, from the statement.

[P + 1.345 L²atm/mol² / (0.7564L/10.21mol)² ] (0.7564L/10.21mol - 3.219×10-2 L/mol ) = 0.082 L.atm/mol.K  .  296.9K

[P + 1.345 L²atm/mol² / 5.48X10⁻³ L²/mol²] (0.074 L/mol - 3.219×10-2 L/mol ) = 0.082 L.atm/mol.K  .  296.9K

(P + 245.05 atm) (0.04181L/mol) = 0.082 L.atm/mol.K  .  296.9K

(P + 245.05 atm) (0.04181L/mol) = 24.34 L.atm/mol

0.04181L/mol .P + 10.24 L.atm/mol = 24.34 L.atm/mol

0.04181L/mol .P = 24.34 L.atm/mol - 10.24 L.atm/mol

0.04181L/mol. P = 14.1 L.atm/mol

P = 14.1 L.atm/mol / 0.04181 mol/L

P = 337.2 atm

4 0
3 years ago
What are the three was main States of matter?
OleMash [197]

Answer:

liquid, solid, gas

Explanation:

7 0
4 years ago
Read 2 more answers
The ksp value for lead(ii chloride is 2.4 × 10?4. what is the molar solubility of lead(ii chloride?
charle [14.2K]
Molar solubility is number of moles of the solute that can be dissolved per liter of solution before the solution becomes saturated. 

The molar solubility of lead(ii) chloride with ksp value of 2.4 × 10e4 can be solve as: 

Ksp = s2 = 2.4 × 10e4
s2 = 2.4 × 10e4
s = √(2.4 × 10e4)
s =  154.9 mol/L
6 0
3 years ago
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