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3 years ago

How many grams are in 5.66 mol of caco3?

2 answers:

6 0

To calculate the mass of a given number of moles of a substance, it is important to determine the molar mass of the substance. For CaCO3, the molar mass is equal to 100.09 g / mol. We calculate as follows:

5.66 mol CaCO3 ( 100.09 g / mol ) = 566.51 grams of CaCO3

nalin [4]3 years ago

3 0

When you have a substance made of some molecules you need to know each mass, in this case, CaCO3 has one atom of Ca, one atom of C and three of O.

Ca: 40.078 grams per mol

C: 12.011 grams per mol

O: 15.999 gramps per mol

[Ca+C+(O*3)]= 1 mol

[40.078 + 12.011 + (3*15.999)]=100.086 grams per mol

Now, they ask you about 5.66 moles. You could do a cross multiplication and say:

1mol-------100.086 grams

5.66mol----X= 566,48676 grams = 566,5 grams

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2 years ago

How many atoms are there in 8.88 g Si?

Mariana [72]

Answer:

$\boxed {\boxed {\sf 1.90 \times 10^{23} \ atoms \ Si}}$

Explanation:

We are asked to find how many atoms are in 8.88 grams of silicon.

<h3>1. Grams to Moles </h3>

First, we convert grams to moles. We use the molar mass or the mass of 1 mole of a substance. These values are found on the Periodic Table as they are equal to the atomic masses, but the units are grams per mole instead of atomic mass units.

Look up silicon's molar mass.

Si: 28.085 g/mol

We will convert using dimensional analysis. Set up a conversion factor with the molar mass.

$\frac { 28.085 \ g \ Si}{1 \ mol \ Si}$

We are converting 8.88 grams of silicon to moles, so we multiply by this value.

$8.88 \ g \ Si *\frac { 28.085 \ g \ Si}{1 \ mol \ Si}$

Flip the fraction so the units of grams of silicon cancel.

$8.88 \ g \ Si *\frac{1 \ mol \ Si} { 28.085 \ g \ Si}$

$8.88 *\frac{1 \ mol \ Si} { 28.085 }$

$\frac {8.88} { 28.085 } \ mol \ Si$

$0.316183015845 \ mol \ Si$

<h3>2. Moles to Atoms </h3>

Next, we convert moles to atoms. We use Avogadro's Number or 6.022 × 10²³. This is the number of particles (atoms, molecules, formula units, etc.) in 1 mole of a substance. In this case, the particles are atoms of silicon.

Set up another conversion factor.

$\frac {6.022 \times 10^{23} \ atoms \ Si}{1 \ mol \ Si}$