All categories

3 years ago

Find the mass of 1.00 mol NaCl

Chemistry

2 answers:

Mnenie [13.5K]3 years ago

8 0

Answer: One mol of NaCl (6.02 x1023 formulas) has a mass of 58.44 g.

To go from grams to moles, divide the grams by the molar mass. 600 g58.443 g/mol = 10.27 mol of NaCl.

<h3>HOPE THIS HELPS HAVE A AWESOME DAY❤️✨</h3>

Explanation:

satela [25.4K]3 years ago

6 0

The answer is 10.27 mol NaCl

You might be interested in

What is your question in climate change?

Kruka [31]

Answer:

Why has my town experienced record-breaking cold and snowfall if the climate is warming? Is there scientific consensus that people are causing today's climate change? Do natural variations in climate contribute to today's climate change?

Explanation:

Yan po ang answer tama po yan

8 0

2 years ago

Read 2 more answers

Electrons aren’t just smaller than atoms .electrons are part of

Gnom [1K]

Elections are part of a negatively charged particle from an atom

3 0

4 years ago

A 544 mg of a mixture of fluorene and benzoic acid was weighed out and subjected to an extraction and recrystallization. After t

butalik [34]

<u>Answer:</u> The percent composition of fluorene is 33.08 % and benzoic acid is 36.03 %.

<u>Explanation:</u>

We are given:

Mass of mixture = 544 mg

Mass of fluorene after purification = $1.80\times 10^2mg=180mg$

Mass of benzoic acid after purification = 196 mg

To calculate the percentage composition of a substance in a mixture, we use the equation:

$\%\text{ composition of substance}=\frac{\text{Mass of substance}}{\text{Mass of mixture}}\times 100$

<u>For fluorene:</u>

$\%\text{ composition of fluorene}=\frac{180}{544}\times 100=33.08\%$

Hence, the percent composition of fluorene is 33.08 %

<u>For benzoic acid:</u>

$\%\text{ composition of benzoic acid}=\frac{196}{544}\times 100=36.03\%$

Hence, the percent composition of benzoic acid is 36.03 %

5 0

4 years ago

Draw the organic product formed when ch3ch2c≡c−na+ reacts with (ch3)2chch2ch2cl. click the "draw structure" button to launch the

Viktor [21]

Explanation:

Given that sodium butylite is reacting with 1-chloro-3-methyl butane. In a reaction 6-methyl nona-3-yne and sodium chloride will be obtained as product.

The chemical reaction:

$CH_3-CH_2C\equiv C-Na^++(CH_3)_2CH-CH_2-CH_2-Cl\rightarrow CH_3-CH_2C\equiv C-CH_2-CH_2-(CH_3)_2+NaCl$

The reaction is also attached as image for reference.

6 0

3 years ago

The

goldfiish [28.3K]

Answer: …

Explanation:

5 0

2 years ago