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Evgen [1.6K]
2 years ago
15

A current carrying wire is placed vertically. the magnetic field around the wire is rotating clockwise around the wire. what dir

ection is the current moving?
Physics
1 answer:
Fittoniya [83]2 years ago
8 0

A current carrying wire is placed vertically. The magnetic field around the wire is rotating clockwise around the wire. The current is moving from top to bottom

Holding a current carrying wire in your right hand with the thumb pointing in the direction of current flow, the fingers wrapping the wire will portray the magnetic lines of force direction, following the right-hand thumb rule.

As a result, a current carrying conductor is vertically held. If you follow the rule, the current should be passed through it to generate a clockwise magnetic field around the conductor from top to bottom.

To learn more about currents: brainly.com/question/14411049

#SPJ4

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Which type of electromagnetic radiation is most likely to cause sunburn?
MrMuchimi
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3 years ago
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A physics student with too much free time drops a watermelon from a roof of a building, hears the sound of the watermelon going
tatiyna

Answer:

28.6260196842 m

Explanation:

Let h be the height of the building

t = Time taken by the watermelon to fall to the ground

Time taken to hear the sound is 2.5 seconds

Time taken by the sound to travel the height of the cliff = 2.5-t

Speed of sound in air = 340 m/s

For the watermelon falling

s=ut+\frac{1}{2}at^2\\\Rightarrow h=0t+\frac{1}{2}\times 9.81\times t^2\\\Rightarrow h=\frac{1}{2}\times 9.81\times t^2

For the sound

Distance = Speed × Time

\text{Distance}=340\times (2.5-t)

Here, distance traveled by the stone and sound is equal

\frac{1}{2}\times 9.81\times t^2=340\times (2.5-t)\\\Rightarrow 4.905t^2=340\times (2.5-t)\\\Rightarrow t^2=\frac{340}{4.905}(2.5-t)\\\Rightarrow t^2+69.3170234455t-173.292558614=0

t=\frac{-69.31702\dots +\sqrt{69.31702\dots ^2-4\cdot \:1\cdot \left(-173.29255\dots \right)}}{2\cdot \:1},\:t=\frac{-69.31702\dots -\sqrt{69.31702\dots ^2-4\cdot \:1\cdot \left(-173.29255\dots \right)}}{2\cdot \:1}\\\Rightarrow t=2.4158\ s\ or\ -71\ seconds

The time taken to fall down is 2.4158 seconds

h=\frac{1}{2}\times 9.81\times 2.4158^2=28.6260196842\ m

Height of the buidling is 28.6260196842 m

7 0
4 years ago
A mass weighing 4 lb stretches a spring 4in. Suppose the mass is given an additional in displacement downwards and then released
anastassius [24]

Answer:

4√6 rad/s

Explanation:

Since the spring is initially stretched a length of x = 4 in when the 4 lb mass is placed on it, since it is in equilibrium, the spring force, F = kx equals the weight of the mass W = mg.

So, W = F

mg = kx where m = mass = 4lb, g = acceleration due to gravity = 32 ft/s², k = spring constant and x = equilibrium displacement of spring = 4 in = 4 in × 1ft /12 in = 1/3 ft

making k the spring constant subject of the formula, we have

k = mg/x

substituting the values of the variables into the equation, we have

k = mg/x  

k = 4 lb × 32 ft/s² ÷ 1/3 ft

k = 32 × 4 × 3

k = 384 lbft²/s²

Now, assuming there is no friction and no external force, we have an undamped system.

So, the natural frequency for an undamped system, ω = √(k/m) where k = spring constant = 384 lbft²/s² and m = mass = 4 lb

So, substituting the values of the variables into the equation, we have

ω = √(k/m)

ω = √(384 lbft²/s² ÷ 4 lb)

ω = √96

ω = √(16 × 6)

ω = √16 × √6

ω = 4√6 rad/s

5 0
3 years ago
PLEASE HELP!! DUE IN 40 MINUTES!!
Irina18 [472]

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6 0
3 years ago
The apparent visual magnitude of a star is 7.3. This tells us that the star is _______.
fredd [130]

Answer:

Option (B)

Explanation:

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The given visual magnitude of a star is 7.3, and is comparatively very less brighter. This shows a relatively very large distance from the earth and due to this large distance and low luminousity, this star is not visible to our naked eye.

Thus, the correct answer is option (B).

8 0
4 years ago
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