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3 years ago

Liquid water can be separated into hydrogen gas and oxygen gas through electrolysis. 1 mole of hydrogen gas and 0.5 moles of

Physics

1 answer:

den301095 [7]3 years ago

8 0

The temperature of the oxygen gas is 243.75 K.

Using ideal gas law to explain the answer, the absolute temperature of the gas will decrease if the number of moles of the gas increases and it will increase if the volume and/or pressure of the gas increases.

The reaction of the given elements;

$H_2 \ + \ \frac{1}{2} O_2 \ --->\ \ H_2O$

volume of the collected oxygen gas, V = 10 L

pressure of the gas, P = 1 atm

number of moles of the gas, n = 0.5

Using ideal law the temperature of the oxygen gas is calculated as follows;

$PV = nRT\\\\T = \frac{PV}{nR} \\\\where;\\R \ is \ the \ ideal \ gas \ constant = 0.08205 \ L.atm/K.mol\\\\T = \frac{1 \times 10 }{0.5 \times 0.08205} \\\\T = 243.75 \ K$

Thus, the temperature of the gas is 243.75 K.

Using ideal gas law to explain the answer. The absolute temperature of the oxygen gas is directly proportional to the product of its pressure and volume and inversely proportional to its number of moles. That is the absolute temperature of the gas will decrease if the number of moles of the gas increases and it will increase if the volume and/or pressure increases.

Learn more here: brainly.com/question/16617695

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If an object has a mass of 1417g and it is moved 47 meters in 90 seconds, how much power was used?

astraxan [27]

Mass of the object is given as

$m = 1417 g = 1.417 kg$

now the speed of object is given as

$v = \frac{d}{t}$

here we know that

$d = 47 m$

$t = 90 s$

now we will have

$v = \frac{47}{90} = 0.52 m/s$

now we will have kinetic energy of the object as

$KE = \frac{1}{2}mv^2$

$KE = \frac{1}{2}(1.417)(0.52)^2$

$KE = 0.19 J$

now the power is defined as rate of energy

so here we can find power as

$P = \frac{KE}{t}$

$P = \frac{0.19}{90} = 2.14\times 10^{-3} W$

so above is the power used for the object

3 0

3 years ago

Gases tend to deviate from the ideal gas law at

IgorLugansk [536]

<h2>Answer: high pressures</h2>

The Ideal Gas equation is:

$P.V=n.R.T$

Where:

$P$ is the pressure of the gas

$n$ the number of moles of gas

$R=0.0821\frac{L.atm}{mol.K}$ is the gas constant

$T$ is the absolute temperature of the gas in Kelvin.

According to this law, molecules in gaseous state do not exert any force among them (attraction or repulsion) and the volume of these molecules is small, therefore negligible in comparison with the volume of the container that contains them.

Now, real gases can behave approximately to an ideal gas, under the conditions described above.

However, when <u>temperature is low</u> these gases deviate from the ideal gas behavior, because the molecules move slowly, allowing the repulsion or attraction forces to take effect.

The same happens at <u>high pressures</u>, because the volume of molecules is no longer negligible.

5 0

4 years ago

a concrete slab 20 m long and weighing 400,000 N is supported by one pillar. A 19,600 N car is parked 8 meters from one end, whe

Elden [556K]

let the distance of pillar is "r" from one end of the slab

So here net torque must be balance with respect to pillar to be in balanced state

So here we will have

$Mg(r - L/2) = mg(L/2 - 8)$

here we know that

mg = 19600 N

Mg = 400,000 N

L = 20 m

from above equation we have

$400,000(r - 10) = 19,600 (10 - 8)$

$r - 10 = 0.098$

$r = 10.098 m$

so pillar is at distance 10.098 m from one end of the slab

3 0

3 years ago

In research in cardiology and exercise physiology, it is often important to know the mass of blood pumped by a person's heart in

frez [133]

Answer:

0.05081 kg

Explanation:

$m_1$ = Mass of blood

$v_1$ = 0.435 m/s

$m_2$ = Mass of subject and pallet = 54 kg

$v_2$ = Velocity of subject and pallet = $\dfrac{Distance}{Time}=\dfrac{6.55\times 10^{-5}}{0.16}=0.000409375\ m/s$

In this system the linear momentum is conserved so,

$m_1v_1=m_2v_2\\\Rightarrow m_1=\dfrac{m_2v_2}{v_1}\\\Rightarrow m_1=\dfrac{54\times 0.000409375}{0.435}\\\Rightarrow m_1=0.05081\ kg$

The mass of blood is 0.05081 kg

8 0

3 years ago

A motor does 20. joules of work on a block, accelerating the block vertically upward. Neglecting friction, if the gravitational

Eva8 [605]

The motor does 20 J of work on the block, it means that the total mechanical energy of the block has increased by 20 J. But the increase in total mechanical energy is equal to the sum of the increases in potential energy and kinetic energy:
$\Delta E = \Delta U + \Delta K$
So, if the gravitational potential energy has increased by 15 J, the kinetic energy has increased by
$\Delta K = \Delta E - \Delta U = 20 J - 15 J= 5 J$

4 0

3 years ago