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Ronch [10]
3 years ago
5

Uranium-235 Fission

Physics
1 answer:
ExtremeBDS [4]3 years ago
4 0

In the balanced nuclear reaction of uranium 235, we have thorium 231, helium atom and energy released at the right of the equation

<h3>Balanced nuclear reaction of Uranium</h3>

The balanced nuclear reaction of uranium is determined as follows;

^{235}_{92}U\ --- > \ ^4_2He\ + \ ^{231}_{90}Th\ + \ energy

Thus, in the balanced nuclear reaction of uranium 235, we have thorium 231, helium atom and energy released at the right of the equation while uranium 235 is on the left hand side of the nuclear reaction equation.

Learn more about nuclear reaction here:

brainly.com/question/25387647

#SPJ1

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A ladybug sits 14 cm from the center of a turntable spinning at 33.33 rpm. The Sun is shining horizontally through the window an
kolbaska11 [484]

Answer:

The maximum velocity is 0.489 m/s

Explanation:

Maximum velocity (v) = angular velocity (w) × radius (r)

w = 33.33 rpm = 33.33×0.1047 = 3.4897 rad/s

r = 14 cm = 14/100 = 0.14 m

v = 3.4897×0.14 = 0.489 m/s

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3 years ago
The largest building in the world by volume is the boeing 747 plant in Everett, Washington. It measures approximately 632 m long
Schach [20]

Explanation:

Given that,

The dimensions of the largest building in the world is 632 m long, 710 yards wide, and 112 ft high. It basically forms a cuboid. The volume of a cuboidal shape is given by :

Since,

1 meter = 3.28084 feet

632 m = 2073.49 feet

1 yard= 3 feet

710 yards = 2130 feet

V = lbh

V=2073.49 \ ft\times 2130\ ft\times 112\ ft

V=494651774.4\ ft^3

V=4.94\times 10^8\ ft^3

Also,

V=(4.94\times 10^8\ ft^3)(\dfrac{1\ m}{3.281})^3

V=1.39\times 10^7\ m^3

Hence, this is the required solution.

3 0
4 years ago
Two forces P and Q act on an object of mass 15.0 kg with Q being the larger of the two forces. When both forces are directed to
Rom4ik [11]

Answer:

P=6.25N  and Q=16.25N

Explanation:

In order to solve this problem we must first draw a free body diagram for both situation, (see attached picture).

Now, we need to analyze the two free body diagrams. So let's analyze the first diagram. Since the body is accelerated, then the sum of forces is equal to mass times acceleration, so we get:

\Sigma F=ma

We can assume there will be only the two mentioned forces P and Q, so

the sum of forces will be:

P+Q=ma

P+Q=(15kg)(1.50m/s^{2})

P+Q=22.5N

We can do the same analysis for the second free body diagram:

\Sigma F=ma

Q-P=(15kg)(0.7m/s^{2})

Q-P=10.5N

so now we have a system of equations we can solve by elimination:

Q+P=22.5N

Q-P=10.5N

Now, we can add the two equations together so the P force is eliminated, so we get:

2Q=32.5N

now we can solve for Q:

Q=\frac{32.5N}{2}

so

Q=16.25N

Now we can use any of the equations to find P.

Q+P=22.5N

P=22.5N-Q

when substituting for Q we get:

P=22.5N-16.25N

so

P=6.25N

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4 years ago
The standard unit for measuring volume is the _____.
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3 years ago
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