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Ronch [10]
2 years ago
5

Uranium-235 Fission

Physics
1 answer:
ExtremeBDS [4]2 years ago
4 0

In the balanced nuclear reaction of uranium 235, we have thorium 231, helium atom and energy released at the right of the equation

<h3>Balanced nuclear reaction of Uranium</h3>

The balanced nuclear reaction of uranium is determined as follows;

^{235}_{92}U\ --- > \ ^4_2He\ + \ ^{231}_{90}Th\ + \ energy

Thus, in the balanced nuclear reaction of uranium 235, we have thorium 231, helium atom and energy released at the right of the equation while uranium 235 is on the left hand side of the nuclear reaction equation.

Learn more about nuclear reaction here:

brainly.com/question/25387647

#SPJ1

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Calculate the energy of a photon of electromagnetic radiation whose frequency is 2.94 x 10 to the 14th xbox one
DIA [1.3K]

Answer:

1.95\cdot 10^{-19} J

Explanation:

The energy of a photon is given by:

E=hf

where

h=6.63\cdot 10^{-34}Js is the Planck constant

f=2.94\cdot 10^{14} Hz is the frequency of the photon

Substituting the numbers into the equation, we find:

E=(6.63\cdot 10^{-34} Js)(2.94\cdot 10^{14} Hz)=1.95\cdot 10^{-19} J

3 0
2 years ago
A jet with mass m = 90000.0 kg jet accelerates down the runway for takeoff at 1.6 m/s2.
leva [86]
This question requires the use of the equation of motion:
v = u + at [v is final velocity (0), u is initial velocity (24), a is acceleration, t is time (13)]
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F = ma (F is force, m is mass, a is acceleration)
First, we calculate the acceleration:
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6 0
3 years ago
. A student thinks that the more protons an atom has, the more reactive it will be. Which will best disprove this student's idea
shepuryov [24]
The best answer to the question that is being stated above would be the first choice. To disprove the claims of the student that you need more protons to have more reactivity, then you proceed to compare the reactivities of lithium (Li) and krypton (Kr). Krypton has more protons than Lithium, but it is less reactive because it is a noble gas.
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7 0
3 years ago
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E)
guapka [62]

Answer:

Pressure, P = 32666.66 Pa

Explanation:

It is given that,

Surface area of foot of Bimaba is 150 cm² or 0.015 m².

Her weight is 50 kg

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P=\dfrac{F}{A}\\\\P=\dfrac{mg}{A}\\\\P=\dfrac{50\times 9.8}{0.015}\\\\P=32666.66\ Pa

So, the pressure is 32666.66 Pa.

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