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Ronch [10]
2 years ago
5

Uranium-235 Fission

Physics
1 answer:
ExtremeBDS [4]2 years ago
4 0

In the balanced nuclear reaction of uranium 235, we have thorium 231, helium atom and energy released at the right of the equation

<h3>Balanced nuclear reaction of Uranium</h3>

The balanced nuclear reaction of uranium is determined as follows;

^{235}_{92}U\ --- > \ ^4_2He\ + \ ^{231}_{90}Th\ + \ energy

Thus, in the balanced nuclear reaction of uranium 235, we have thorium 231, helium atom and energy released at the right of the equation while uranium 235 is on the left hand side of the nuclear reaction equation.

Learn more about nuclear reaction here:

brainly.com/question/25387647

#SPJ1

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our friend is constructing a balancing display for an art project. She has one rock on the left (ms=2.25 kgms=2.25 kg) and three
Licemer1 [7]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

The torque produced by the pile of rocks is \tau = 35.63\ N \cdot m  

b

The distance of the single for equilibrium to occur is r_s =1.62 \ m

Explanation:

From the question we are told that

     The mass of the left rock is  m_s = 2.25 \ kg

     The mass of the rock on the right m_p = 10.1 kg

    The distance from  fulcrum to the center of the pile of rocks is  r_p = 0.360 \ m

   

Generally the torque produced by the pile of rock is mathematically represented as

           \tau = m_p * g * r_p

Substituting values

         \tau = 10.1 * 9.8  * 0.360                  

          \tau = 35.63\ N \cdot m      

Generally we can mathematically evaluated the distance of the the single rock that would put the system in equilibrium as follows

   The torque due to the single rock is

           \tau = m_s  * g * r_s

At equilibrium the both torque are equal

            35.63 = m_s * r_s * g

Making r_s the subject of the formula

             r_s = \frac{35.63 }{m_s * g}

Substituting values

            r_s = \frac{35.63 }{2.25 * 9.8}

            r_s =1.62 \ m

6 0
3 years ago
During anomalous expansion of water ,heat transfer is limited to conduction and radiation only ,explain.​
aalyn [17]

Heat transfer is limited to conduction and radiation only in anomalous expansion of water simply because of the temperature at which the expansion occurs and density

<h3>What is anomalous expansion of water?</h3>

Anomalous expansion of water is a property of water in which water expands instead of contracting.

  • Anomalous expansion of water makes water less dense.
  • The major effect of this anomalous expansion it will still remain less dense and at the surface of water.
  • Interestingly, this expansion occurs when it is cooled from 4°C to 0°C.

Learn more about properties of water:

brainly.com/question/18681949

4 0
2 years ago
What are the Rules of magnetism
Keith_Richards [23]

all the allials must be aligned in the same direction

magnets are affected by heat, drops, and improper storage

3 0
3 years ago
Where do seasons alternate between a very dry season and a monsoon season, with a stable warm climate?
Angelina_Jolie [31]
That would be a savanna climate
7 0
4 years ago
If the original pressure is 5 atm and original volume is 100 L, and the new volume is 20 L, what is the new pressure?
Nana76 [90]
P1V1=P2V2
5*100=P2*20
500=20P
P=25
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3 years ago
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