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3 years ago

Which type of electromagnetic radiation is most likely to cause sunburn?

Physics

2 answers:

expeople1 [14]3 years ago

6 0

The answer is Ultraviolet

MrMuchimi3 years ago

3 0

-The Answer is A Ultraviolet-

Explanation: UVA (Ultraviolet) rays can cause serious damage to your skin.

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a chemical reaction a temperature change may occur because of the breaking or formation of chemical bonds that release excess en

Hoochie [10]

Answer:

it cannot be considered a physical change because it occur from the chemical reaction.

Explanation:

because physical change is the change of the size,volume, density,flexibility. in other words its a change in the outer appearance or change in which we can see or feel without using a tool or a machine

hope it help just my opinion

5 0

4 years ago

Amber is a (a) metal (b) rubber (c) resin (d) sugar

zlopas [31]

Answer:

c. Resin.

Explanation:

Amber is a resin.

4 0

2 years ago

Germany, Italy, and Japan signed what official declaration of alliance on September 27, 1941, forming the Axis powers?

lisov135 [29]

A. they formed the tripartite pact

7 0

3 years ago

suppose you need to build a raft to cross a fast-moving river. describe the physical and chemical properties of the raft that wo

alisha [4.7K]

Physical: the raft needs to float, which means what you make the raft out of must be less dense than water.
The raft would need sturdiness- if the raft is frail, the water might break it
Chemical: It can not react with water and it can not be made of a completely soluable substance (something that would dissolve in it like salt)

6 0

3 years ago

Frank’s automobile engine runs at 100∘C. One day, when the outside temperature is 15∘C, he turns off the ignition and notes that

lapo4ka [179]

Answer:

the engine cool to 40 $^{o}C$ at 14.07 minutes

Explanation:

Given information

T(5) = 70 $^{o}C$

$T_{0}$ = 100 $^{o}C$

C = 15 $^{o}C$

Newton's law of cooling :

T(t) = C + ( $T_{0}$ - C) $e^{-kt}$

where

T(t) = temperature at any given time

C = surrounding temperature

$T_{0}$ = initial temperature of heated object

k = cooling constant

to find the the time when the engine will be cooled down to 40 $^{o}C$ , we first need to find the cooling constant, k

when t = 5, T(5) = 70 $^{o}C$

so,

T(t) = C + ( $T_{0}$ - C) $e^{-kt}$

T(5) = 15 + (100 - 15) $e^{-5k}$

70 = 15 + (85) $e^{-5k}$

$e^{-5k}$ = (70 - 15) / 85

-5k = ln (55/85)

k = - ln (55/85) / 5

k = 0.087

thus, we have the eqaution

T(t) = 15 + (85) $e^{-0.087t}$

now we can determine the time when T(t) = 40 $^{o}C$

40 = 15 + (85) $e^{-0.087t}$

$e^{-0.087t}$ = (40-15)/85

-0.0087t = ln (25/85)

t = - ln (25/85)/0.087

t = 14.07 minutes

8 0

3 years ago