5 bonus on 50 is 5/50 *100%=10%
5 bonus on 100 is 5/100 *100%=5%
Answer: for 50 points.
Answer: 3/5
Step-by-step explanation: simplified completely
Answer:
6
Step-by-step explanation:
15 - 9
24 nitrate I’m pretty sure but not so sure but I’m pretty sure but not so sure
Answer:
a) Interval containing the corresponding P-value for a two-tailed test is;
0.01 ≤ p-value ≤ 0.02
b) Interval containing the corresponding P-value for a right-tailed
test is;
0.005 < p-value < 0.010
Step-by-step explanation:
Given the data in the question;
t = 2.930
df = 10
Test statistics;
Now form the t-distribution table, at df = 10, 2.930 falls between { t=2.764 and t=3.169]
so;
for a two tailed test, corresponding p-value is between: 0.02 and 0.01
For one(right) tailed test, corresponding p-value is between: 0.01 and 0.005
Therefore;
a) Interval containing the corresponding P-value for a two-tailed test is;
0.01 ≤ p-value ≤ 0.02
b) Interval containing the corresponding P-value for a right-tailed
test is;
0.005 < p-value < 0.010
