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andre [41]
2 years ago
15

You know the following about a coordination compound:(1) The partial empirical formula is KM(CrO₄)Cl₂(NH₃)₄.(2) It has A (red) a

nd B (blue) crystal forms.(3) When 1.0 mol of A or B reacts with 1.0 mol of AgNO3,0.50 mol of a red precipitate forms immediately.(4) After the reaction in (3), 1.0 mol of A reacts very slowly with 1.0 mol of silver oxalate (Ag₂C₂O₄) to form 2.0 mol of a white precipitate. (Oxalate can displace other ligands.)(5) After the reaction in (3), 1.0 mol of B does not react further with 1.0 mol of AgNO₃.From this information, determine the following:(b) The group(s) bonded to M ionically and covalently
Chemistry
1 answer:
melisa1 [442]2 years ago
8 0

coordination compound, any of a class of substances with chemical structures in which a central metal atom is surrounded by nonmetal atoms or groups of atoms, called ligands, joined to it by chemical bonds.

<h3>How do you write a coordination compound?</h3>

Order of naming ions: Simple or complex positive ion always named first followed accompany the negative ion. The name is started with a small letter and the complex part is written as one word, e.g. [Co(NH3)6] Cl3, hexa amminecobalt (III) chloride.

<h3>Why are complex compounds called coordination?</h3>

This type of bonding is different from a normal covalent bond in which each atom supplies one electron. If the coordination complex carries a net charge, the complex is called a complex ion. Compounds that contain a coordination complex are called coordination compounds.

Learn more about coordination compounds here:

<h3 /><h3>brainly.com/question/27289242</h3><h3 /><h3>#SPJ4</h3>
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The photodissociation of ozone by ultraviolet light in the upper atmosphere is a first-order reaction with a rate constant of 1.
atroni [7]

Answer:

[O₃]= 8.84x10⁻⁷M  

Explanation:

<u>The photodissociation of ozone by UV light is given by:</u>

O₃ + hν → O₂ + O (1)

<u>The first-order reaction of the equation (1) is:</u>

rate = k [O_{3}] = - k \frac{\Delta [O_{3}]}{\Delta t} (2)

<em>where k: is the rate constant and Δ[O₃]/Δt: is the variation in the ozone concentration with time, and the negative sign is by the decrease in the reactant concentration </em>    

<u>We can get the following expression of the </u><u>first-order integrated law</u><u> of the reaction (1), by resolving the equation (2):</u>

[O_{3}]_{t} = [O_{3}]_{0} \cdot e^{-kt} (3)

<em>where [O₃](t): is the ozone concentration in the elapsed time and [O₃]₀: is the initial ozone concentration</em>

We can calculate the initial ozone concentration using equation (3):  

[O_{3}]_{t} = 5.0 \cdot 10^{-3}M \cdot e^{-(1.0\cdot 10^{-5}s^{-1}) (\frac{10d \cdot 24h \cdot 3600 s}{1d \cdot 1h})} = 8.84 \cdot 10^{-7}M

So, the ozone concentration after 10 days is 8.84x10⁻⁷M.

I hope it helps you!                    

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