<u>Answer:</u>
<u>For 1:</u> The value of
for the chemical equation is -24.636 kJ/mol
<u>For 2:</u> The value of
for the chemical equation is -20.925 kJ/mol
<u>Explanation:</u>
For the given chemical equation:

To calculate the
for given value of equilibrium constant, we use the relation:
.....(1)
where,
= ? kJ/mol
R = Gas constant = 
T = temperature = 2000 K
= equilibrium constant in terms of partial pressure = 4.40
Putting values in above equation, we get:

Converting this into kilo joules, we use the conversion factor:
1 kJ = 1000 J
So, -24636.12 J/mol = -24.636 kJ/mol
Hence, the value of
for the chemical equation is -24.636 kJ/mol
The expression of
for the given chemical equation is:

We are given:

Putting values in above equation, we get:

Now, calculating the value of
by using equation 1:
R = Gas constant = 
T = temperature = 2000 K
= equilibrium constant in terms of partial pressure = 3.52
Putting values in equation 1, we get:

Converting this into kilo joules, we use the conversion factor:
1 kJ = 1000 J
So, -20925.68 J/mol = -20.925 kJ/mol
Hence, the value of
for the chemical equation is -20.925 kJ/mol