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lukranit [14]
3 years ago
8

Before the fire, the forest consists of large trees. After the fire, there is only ash. Explain what the law of conservation of

matter suggests happened to the rest of the mass of the trees.
Chemistry
1 answer:
Tasya [4]3 years ago
5 0

Answer: explained below

Explanation:

Matter can change form through physical and chemical changes, but through any of these changes, matter is conserved. The same amount of matter exists before and after the change—none is created or destroyed.

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Atomic mass of 14.01 amu
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What is the element with 7 protons?  They probably also have 7 neutrons.  Just a ball park figure guess.
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What’s the answer to this?
MArishka [77]

Benzene

  • Benzene has low density than the water itself of about 0.9 g/cm³

Low denisty object than the water usually <u>floats on the water</u>.

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2 years ago
Why when magnesium and chlorine bond there is one magnesium for every two chloride ions
xenn [34]

Magnesium and chlorine form an ionic bond. Covalent bonds are formed when two or more atoms share electrons between them. ... So two chlorine anions form an ionic bond with one magnesium cation for form MgCl2, a neutral chemical compound.

5 0
3 years ago
Ethanol has a Kb of 1.22 °C/m and usually boils at 78.4 °C. How many mol of an nonionizing solute would need to be added to 48.8
Galina-37 [17]

Answer:

0.272 mol

Explanation:

∆Tb = m × Kb

∆Tb = 85.2°C - 78.4°C = 6.8°C

Kb = 1.22°C/m

mass of ethanol = 48.80 g = 48.80/1000 = 0.0488 kg

Let the moles of non-ionizing solute be y

m (molality) = y/0.0488

6.8 = y/0.0488 × 1.22

y = 6.8×0.0488/1.22 = 0.272 mol

6 0
3 years ago
Calculate the total heat required (in joules) to convert 3.95 grams liquid ethanol (C2H5OH) at 25.0 °C to gas at 95.0 °C, given
kumpel [21]

Answer:

The total heat required is 4088.6 J

Explanation:

We have three processes which involve heat absorption. We have to calculate the heat of each process and then to calculate the total heat.

1- liquid ethanol is heated from 25ºC (298 K) to the boiling point 78.5ºc (351.5 K). We use specifi heat of liquid ethanol to calculate the heat absorbed in this part:

H1= m x Sh x ΔT

H1= m x Sh x (Tfinal - Tinitial)

H1= 3.95 g x 2.45 J/g.K x (351.5 K -298 K)

H1= 517.7 J

2- State change: liquid ethanol is vaporized it turns gaseous ethanol The process occur at constant temperature (78.5ºC= 351.5 K). We need the molecular weight of ethanol (2 x 14 + 5 + 16 + 1= 46 g/mol) to cancel mol unit:

H2= m x ΔHvap x 1/Mw

H2= 3.95 g x 40.5 KJ/mol x 1 mol/46 g

H2= 3.477 KJ= 3477 J

3- Gaseous ethanol is heated from 78.5ºC to a final temperature of 95ºC (368 K). We use the specific heat of gaseous ethanol:

H3= m x Sh x ΔT

H3= 3.95 g x 1.43 J/g.K x (368 K - 351.5 K)

H3= 93.2 J

The total heat required is calculated as follows:

Htotal= H1 + H2 + H3

Htotal= 517.7 J + 3477.7 J + 93.2 J

Htotal= 4088.6 J

6 0
3 years ago
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