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Nana76 [90]
3 years ago
12

A congested computer network has a 0.005 probability of losing a data packet and packet losses are independent events. A lost pa

cket must be resent. Round your answers to four decimal places (e.g. 98.7654).
a. What is the probability that an e-mail message with 100 packets will need any resent?
b. What is the probability that an e-mail message with 3 packets will need exactly one to be resent?
c. If 10 e-mail messages are sent, each with 100 packets, what is the probability that at least one message will need some packets to be resent?
Engineering
1 answer:
GenaCL600 [577]3 years ago
3 0

Answer

given,

Probability of loosing data, p = 0.005

 q = 1 - 0.005 = 0.995

a) Probability that none of the need resent in the 100 Pack

  = ¹⁰⁰C₀ p⁰q¹⁰⁰

 = 0.995¹⁰⁰ = 0.6057

 Probability at least one mail is resent = 1 - 0.6057

                                                                = 0.3942

b) Probability that that exactly one out of three needs to be resent is:

   =  ³C₁ p¹q²

   =  3 x 0.005 x 0.995²

   = 0.0149

c) Probability that none of the need resent in the 1000 Pack

  = ¹⁰⁰⁰C₀ p⁰q¹⁰⁰⁰

 = 0.995¹⁰⁰⁰ = 0.006657

 Probability at least one mail is resent = 1 - 0.006657

                                                                = 0.9933

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Answer:

a) T_{L} = 273.378\,K\,(0.228\,^{\textdegree}C), b) \dot Q_{H} = 26.875\,kW

Explanation:

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COP_{HP} = \frac{T_{H}}{T_{H}-T_{L}}

After some algebraic handling, the temperature of the cold reservoir is determined:

T_{H}-T_{L} = \frac{T_{H}}{COP_{HP}}

T_{L} = T_{H}\cdot \left(1-\frac{1}{COP_{HP}}  \right)

T_{L} = (297.15\,K)\cdot \left(1-\frac{1}{12.5}\right)

T_{L} = 273.378\,K\,(0.228\,^{\textdegree}C)

b) The heating load provided by the heat pump is:

\dot Q_{H} = COP_{HP}\cdot \dot W

\dot Q_{H} = (12.5)\cdot (2.15\,kW)

\dot Q_{H} = 26.875\,kW

4 0
3 years ago
Choose two consumer services careers and research online to determine what kinds of professional organizations exist for these p
Tom [10]

Answer:

Market Researcher

The Marketing Research Association (MRA) is a professional organization for market researchers. It provides information to its members on how to improve marketing research for businesses and individuals. The MRA gives its members important industry news and information through their website. Their code for marketing research standards also protects members from bad actors and improves the public perception of marketing research. The association also has a full time lobbyist representing the market research industry before government officials. The MRA has various membership categories as well. The membership fee differs for each category.  

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A credit analyst is a person that reviews consumer or business financial profiles in order to give a loan or credit to them. When a business or individual applies for a credit card, loan, trade account, or another type of financial product whereby a company allows them the use of their money, a credit analyst’s job is to ensure that the consumer or business is willing and able to pay it back in the future. Credit analysts use tools such as credit reports, FICO scores, Dun & Bradstreet ratings, financial statement analyses, and personal references to perform their job. A credit analyst should have a bachelor’s degree with a major in business. Finance and economics majors are particularly suited to a credit analyst position. Certifications are not required, but some credit analysts pursue CPA or CFA (Certified Financial Analyst) designations.

Explanation:

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3 years ago
(c) As Engineering and Computing students, you must be familiar, with the respective professional bodies, as well as, Rules of P
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The professional ethics for computer engineers are:

  • They will Contribute to society and to human well-being.
  • They will  Avoid harm.
  • Be honest and trustworthy.
  • They will be fair and take action that do to discriminate others.

<h3>What are the Characteristics of Code of Ethics?</h3>

The code of ethics are known to be a kind of a universal moral values, that is one that state that what a person expect of any given employee such as been trustworthy, respectful, responsible, and others.

Note that Rules of Practice, Professional Obligations and Codes of Ethics. are known to be put in place to avoid issues that may lead to conflict.

Therefore, i believe that  As Engineering and Computing students, the respective professional bodies, Rules of Practice, Professional Obligations and Codes of Ethics are good and acts as a check and balance to us.

Therefore, The professional ethics for computer engineers are:

  • They will Contribute to society and to human well-being.
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  • They will be fair and take action that do to discriminate others.

Learn more about Engineering rules from

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4 0
1 year ago
For metallurgical reasons, it is desirable to melt the weld metal with minimum energy input. Which one of the following heat sou
stellarik [79]

Answer:

The correct option is;

(a) High power density

Explanation:

The power density of a material is the amount of power per unit volume of the material. Power density, in the context of transformers, fuel cells, batteries, motors, and power supply units, is measured with respect to the volume, and the units is given as W/m³

A system such as a capacitor with an high power density has the capacity to put out large energy amount from a small volume. A capacitor with a high power density, can produce the same power output as a car battery and is said to have a high power density.

8 0
3 years ago
The specific volume of a system consisting of refrigerant-134a at 1.0 Mpa is 0.01 m /kg. The quality of the R-134a is: (a) 12.6%
Flura [38]

Answer:

option c is correct

47.2%

Explanation:

given data

consisting of refrigerant = 134 a

volume V = 0.01 m³/kg

pressure P = 1MPa = 1000 kPa

to find out

quality of the R 134a

solution

we will get here value of volume Vf and Vv from pressure table 60 kpa to 3 Mpa for 1 Mpa of R134 a

that is

Vf = 0.0008701 m³/kg

Vv = 0.0203 m³/kg

so we will apply here formula that is

quality = (V - Vf) / (Vv - Vf)    ............1

put here value

quality = (0.01 - 0.0008701 ) / ( 0.0203 - 0.0008701 )

quality = 0.4698

so quality is 47 %

SO OPTION C IS CORRECT

4 0
3 years ago
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