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denpristay [2]
3 years ago
15

In dynamics, the friction force acting on a moving object is always a) in the same direction of its motion b) a kinetic friction

c) a static friction d) zero
Engineering
1 answer:
FrozenT [24]3 years ago
6 0

Answer:

B) a kinetic friction

Explanation:

 The force of friction in a movement object its called kinetic friction force (<em>fk).              </em>The net force acting in the direction of the movement its express, according to the Newton second law, like this: F- <em>fk. </em>That expression says that the net force produces an aceleration in the direction of the movement of the object.

 Now if the force its removed, the <em>fk</em> its continue acting in the object but now in the opposite direction. And according to the Newton second law this <em>fk </em>it going to continue acting until the object stay in a still state.

  <u>In conclusion</u>, if an object moves in some direction the kinetic friction force always be opposite to that direction of movement, according to the Newton second law

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3 years ago
1. Which of the following will cause a spark knock?
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Answer:

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Explanation:

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5 0
3 years ago
The yellow rectangle area is 25% (or 1/4) the area of the blue rhombus. The height (H) of the yellow rectangle is twice as long
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3 0
2 years ago
a cantilever beam 1.5m long has a square box cross section with the outer width and height being 100mm and a wall thickness of 8
djverab [1.8K]

Answer:

a) 159.07 MPa

b) 10.45 MPa

c) 79.535 MPa

Explanation:

Given data :

length of cantilever beam = 1.5m

outer width and height = 100 mm

wall thickness = 8mm

uniform load carried by beam  along entire length= 6.5 kN/m

concentrated force at free end = 4kN

first we  determine these values :

Mmax = ( 6.5 *(1.5) * (1.5/2) + 4 * 1.5 ) = 13312.5 N.m

Vmax = ( 6.5 * (1.5) + 4 ) = 13750 N

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б = \frac{MC}{I}  =  \frac{13312.5 ( 0.112)}{1/12(0.1^4-0.084^4)}  =  159.07 MPa

B) Determine max transverse shear stress

attached below

   ζ = 10.45 MPa

C) Determine max shear stress in the beam

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attached below is the remaining solution

6 0
3 years ago
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