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sveticcg [70]
3 years ago
13

The purpose of pasteurizing milk is to

Engineering
2 answers:
stellarik [79]3 years ago
7 0
The answer to your problem is B
katen-ka-za [31]3 years ago
6 0

Answer:

i think it c

Explanation:

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List six possible valve defects that should be included in the inspection of a used valve?
olchik [2.2K]

Answer:

Valvular stenosis , Valvular prolapse , Regurgitation,

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3 years ago
Which answer best describes the relationship between the left-hand and right-hand panels in both File Explorer and Finder?
Art [367]

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4 0
2 years ago
Two technicians are discussing cylinder honing technician a says a good cross hatch helps to trap the oil and retain it in the c
aleksley [76]

er:

Explanation:Technician A says that primary vibration is created by slight differences in the inertia of the pistons between top dead center and bottom dead center. Technician B says that secondary vibration is a strong low-frequency vibration caused by the movement of the piston traveling up and down the cylinder. Who is correct? O A. Neither Technician A nor B OB. Technician B O C. Both Technicians A and B D. Technician A​

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2 years ago
What’s the difference between quality and quantity
Lesechka [4]
Quality is how good something is. Like how good the material is. Like the quality of the IPhone X is better than the quality of the iPhone 6s + because it has more features and can sustain better hold
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I dont know exactly if that makes sense but there ya go
YW!
4 0
3 years ago
Read 2 more answers
Water flows in a tube that has a diameter of D= 0.1 m. Determine the Reynolds number if the average velocity is 10 diameters per
Cloud [144]

Answer:

a) Re_{D} = 111896.745, b) Re_{D} = 1.119\times 10^{-7}

Explanation:

a) The Reynolds number for the water flowing in a circular tube is:

Re_{D} = \frac{\rho\cdot v\cdot D}{\mu}

Let assume that density and dynamic viscosity at 25 °C are 997\,\frac{kg}{m^{3}} 0.891\times 10^{-3}\,\frac{kg}{m\cdot s}, respectively. Then:

Re_{D}=\frac{(997\,\frac{kg}{m^{3}} )\cdot (1\,\frac{m}{s} )\cdot (0.1\,m)}{0.891\times 10^{-3}\,\frac{kg}{m\cdot s} }

Re_{D} = 111896.745

b) The result is:

Re_{D}=\frac{(997\,\frac{kg}{m^{3}} )\cdot (10^{-6}\,\frac{m}{s} )\cdot (10^{-7}\,m)}{0.891\times 10^{-3}\,\frac{kg}{m\cdot s} }

Re_{D} = 1.119\times 10^{-7}

6 0
3 years ago
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