Answer:
20.87 Pa
Explanation:
The formula for dynamic pressure is given as;
q= 1/2*ρ*v²
where ;
q=dynamic pressure
ρ = density of fluid
v = velocity of fluid
First find v by applying the formula for flow rate as;
Q = v*A where ;
Q= fluid flow rate
v = flow velocity
A= cross-sectional area.
A= cross-sectional vector area of the pipe given by the formula;
A= πr² = 3.14 * 4² = 50.27 in² where r=radius of pipe obtained from the diameter given divided by 2.
Q = fluid flow rate = 105 gpm----change to m³/s as
1 gpm = 0.00006309
105 gpm = 105 * 0.00006309 = 0.006624 m³/s
A= cross-sectional vector area = 50.27 in² -------change to m² as:
1 in² = 0.0006452 m²
50.27 in² = 50.27 * 0.0006452 = 0.03243 m²
Now calculate flow velocity as;
Q =v * A
Q/A = v
0.006624 m³/s / 0.03243 m² =v
0.2043 m/s = v
Now find the dynamic pressure q given as;
q= 1/2 * ρ*v²
q= 1/2 * 1000 * 0.2043² = 20.87 Pa
Answer:
F = 33,324,295.32N
Explanation:
We will first of all find the height at which the plate is inclined. We use sine rule in this case
SinΘ = Opp/hyp
Opp=h, hyp=19m, Θ=35°
h = 19xSin35 = 10.899m
Therefore height h=10.899+4 = 14.899m
We then Calculate Area of the plate
Area = 12x19 = 228m²
Finally, we use an online software to calculate the Hydrostatic pressure
The result from the online computation is attached.
The pressure is p = 146159.19Pa
But pressure p is
Pressure=Force/Area
Making Force the subject
Hydrostatic Force = Pressure x Area
F= 146159.19 x 228 = 33,324,295.32N
F = 33,324,295.32N
I have attached an image showing the shear stresses and direction.
Answer:
Resolved shear stress = 5.6MPa
Explanation:
From the diagram attached,
Cos λ = [(0,-1,1)•(0,0,1)]/[(√(0^2 + (-1)^2 + 1^2)) + (√(0^2 + 0^2 + 1^2))]
= 1/(√2 x√1) = 1/√2
Also, Cos Φ = [(1,1,1)•(0,0,1)]/[(√(1^2 + 1^2 + 1^2)) + (√(0^2 + 0^2 + 1^2))]
= 1/(√3 x√1) = 1/√3
So resolved shear stress (τ resolved) = 13.7 x (1/√2) x (1/√3) = 13.7 x (1/√6) = 5.593 or approximately 5.6MPa
Answer:
A. engineering design process
Explanation:
We are told that John is trying to develop a handheld camera. And that it is unlike any other one that has been developed before.
Now, though he understands what the final product will look like, the camera still required further development and modification. This is simply an engineering design process because it involves finding a need and trying to solve it since he already understands what the final product will be.
Answer:
Check image, right on PLATO
