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Nata [24]
4 years ago
8

WHAT IS THE EFFECT OF ICE ACCRETION ON THE LONGITUDINAL STABILITY OF AN AIRCRAFT?

Engineering
1 answer:
soldier1979 [14.2K]4 years ago
5 0

Answer:

The major effects of ice accretion on the aircraft is that it disturbs the flow of air and effects the aircraft's performance.

Explanation:

The ice accretion effects the longitudinal stability of an aircraft as:

1. The accumulation of ice on the tail of an aircraft results in the reduction the longitudinal stability and  the elevator's efficacy.

2. When the flap is deflected at 10^{\circ} with no power there is an increase in the longitudinal velocity.  

3. When the angle of attack is higher close to the stall where separation occurs in the early stages of flow, the effect of ice accretion are of importance.  

4. When the situation involves no flap  at reduced power setting results in the decrease in aircraft's longitudinal stability an increase in change in coefficient of pitching moment  with attack angle.

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Jordan's dad made a new recipe for dinner. Jordan looked at the food and saw that it was white, yellow, and purple in color. She
zhenek [66]

Answer:

Jordan used her eyes to see the food, her touch to feel the food, and her nose to smell the food, and lastly, but most importantly, she used her mouth to taste the food.

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2 years ago
why did my dirtbike just stop when i was riding it, and now when i start it it sounds like it has a knock, and wont stay running
chubhunter [2.5K]

Answer: check the engines i swear if ur talking about an actual bike im gonna be so embarrassed lma0

7 0
3 years ago
Read 2 more answers
What are three demonstration drive tips for the vc-turbo engine?.
Oliga [24]

The three (3) demonstration drive tips for a VC-turbo engine are:

  1. Use your gears when overtaking and driving up a long hill.
  2. Warm up your engine before accelerating.
  3. Ensure your oil level is at the optimum gauge or level.

<h3>What is a VC-turbo engine?</h3>

A VC-turbo engine can be defined as a technologically-advanced internal combustion engine that is design and developed to be faster, especially by combining the torque and efficiency of an advanced diesel powertrain with the power of a high-performance gas engine.

<h3>The demonstration drive tips.</h3>

Basically, the three (3) demonstration drive tips for a VC-turbo engine include the following:

  1. Use your gears when overtaking and driving up a long hill.
  2. Warm up your engine before accelerating.
  3. Ensure your oil level is at the optimum gauge or level.

Read more on drive tips here: brainly.com/question/23968178

4 0
3 years ago
A desktop computer is to be cooled by a fan whose flow rate is 0.34 m3 /min. Determine the mass flow rate of air through the fan
Aleks [24]

Answer:

m = 0.238  <u>kg</u>

                  min

r = 0.063m

3 0
3 years ago
Consider a steam turbine, with inflow at 500oC and 7.9 MPa. The machine has a total-to-static efficiency ofηts=0.91, and the pre
sergiy2304 [10]

Answer: \dot m_{in} = 23.942 \frac{kg}{s}, \dot H_{out} = 39632.62 kW

Explanation:

Since there is no information related to volume flow to and from turbine, let is assume that volume flow at inlet equals to \dot V = 1 \frac{m^{3}}{s}. Turbine is a steady-flow system modelled by using Principle of Mass Conservation and First Law of Thermodynamics:

Principle of Mass Conservation

\dot m_{in} - \dot m_{out} = 0

First Law of Thermodynamics

- \dot W_{out} + \eta\cdot (\dot m_{in} \dot h_{in} - \dot m_{out} \dot h_{out}) = 0

This 2 x 2 System can be reduced into one equation as follows:

-\dot W_{out} + \eta \cdot \dot m \cdot ( h_{in}- h_{out})=0

The water goes to the turbine as Superheated steam and goes out as saturated vapor or a liquid-vapor mix. Specific volume and specific enthalpy at inflow are required to determine specific enthalpy at outflow and mass flow rate, respectively. Property tables are a practical form to get information:

Inflow (Superheated Steam)

\nu_{in} = 0.041767 \frac{m^{3}}{kg} \\h_{in} = 3399.5 \frac{kJ}{kg}

The mass flow rate can be calculated by using this expression:

\dot m_{in} =\frac{\dot V_{in}}{\nu_{in}}

\dot m_{in} = 23.942 \frac{kg}{s}

Afterwards, the specific enthalpy at outflow is determined by isolating it from energy balance:

h_{out} =h_{in}-\frac{\dot W_{out}}{\eta \cdot \dot m}

h_{out} = 1655.36 \frac{kJ}{kg}

The enthalpy rate at outflow is:

\dot H_{out} = \dot m \cdot h_{out}

\dot H_{out} = 39632.62 kW

3 0
3 years ago
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