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Alik [6]
1 year ago
12

Use the atomic mass of indium to calculate the relative abundance of indium-113.

Chemistry
1 answer:
ASHA 777 [7]1 year ago
7 0

The relative abundance of indium-113 is 4%.

The isotopes are species of the same element having the same atomic number but a different mass number.

The elements occurring in nature exist as multiple isotopes.

When we take into account the existence of these isotopes and their relative abundance (percent), the average atomic mass of that element can be computed, which is given by the following formula,

Average atomic Mass= (%age of isotope 1) x (Mass of isotope 1) + (%age of isotope 2) x (Mass of isotope 2)/100

Indium exists in the form of Indium-113 and Indium-115.

The mass of Indium-113 is 112.90 u.

The mass of Indium-115 is 114.90 u.

The average atomic mass of Indium is 114.82 u.

Let the %age of isotope 1(Indium-113) be X.

Then, the %age of isotope 2(Indium-115) would be 100-X.

Applying the values in the formula,

Average atomic mass = 112.90X+114.90(100-X)

114.82 = 112.90X+114.90(100-X)

On solving the above equation, the value of X comes out to be 4%.

Thus, the relative abundance/%age abundance of Indium-113 is 4%.

To know more about "Average Atomic Mass", refer to the following link:

brainly.com/question/13753702?referrer=searchResults

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Answer:

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Explanation:

Michaelis–Menten 's equation:

v=V_{max}\times \frac{[S]}{K_m+[S]}=k_{cat}[E_o]\times \frac{[S]}{K_m+[S]}

V_{max}=k_{cat}[E_o]

v = rate of formation of products =

[S] = Concatenation of substrate

[K_m] = Michaelis constant

V_{max} = Maximum rate achieved

k_{cat} = Catalytic rate of the system

[E_o] = Initial concentration of enzyme

We have :

K_m=0.045 mol/dm^3

v=1.15 mmol/dm^3 s=1.15\times 10^{-3} mol/dm^3 s

[S]=0.110 mol/dm^3

v=V_{max}\times \frac{[S]}{K_m+[S]}

1.15\times 10^{-3} mol/dm^3 s=V_{max}\times \frac{0.110 mol/dm^3}{[(0.045 mol/dm^3)+(0.110 mol/dm^3)]}

V_{max}=\frac{1.15\times 10^{-3} mol/dm^3 s\times [(0.045 mol/dm^3)+(0.110 mol/dm^3)]}{0.110 mol/dm^3}=1.620\times 10^{-3} mol/dm^3 s

1.620\times 10^{-3} mol/dm^3 sis the maximum velocity of this reaction.

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3 years ago
Atom , classify it<br><br><br><br><br>helppoppppoeowiie​
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Explanation:

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Leave the answer blank if no precipitate will form. (Express your answer as a chemical formula.) Formula of precipitate ZnCl2(aq
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Answer:

1. Zn(OH)₂ (s)

2. Ag₂CO₃ (s)

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Explanation:

Let's state the equations and we analyse some solubility and precipitation information:

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All salts from carbonates are insoluble

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<h3>What is absorption frequency?</h3>
  • The frequency of the molecular vibration that led to the absorption is the same as the absorption frequency of a basic IR absorption band.
  • In a way, an emission spectrum is the opposite of an absorption spectrum.
  • The discrepancies in the energy levels of each chemical element's orbitals correspond to absorption lines for each chemical element at various particular wavelengths.
  • Therefore, it is possible to identify the constituents in a gas or liquid using its absorption spectrum.
  • Absorption spectroscopy is most frequently used to measure infrared, atomic, visible, ultraviolet (UV), and x-ray waves.

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