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zepelin [54]
3 years ago
8

Combustion analysis of toluene, a common organic solvent, gives 6.45 mg of CO2 and 1.51 mg of H2O. If the compound contains only

carbon and hydrogen, what is its empirical formula?
Chemistry
1 answer:
yan [13]3 years ago
6 0

Answer:

Empirical formula - C_{7}H_{8}

Explanation:

From the given,

Mass of CO_{2} = 6.45 mg= 0.00645 g

Molar mass of carbon = 12 g/mol

Molar mass of CO_{2} = 44 g/mol

Given mass of H_{2}O = 1.51 mg= 0.00151 g

Molar mass of water = 18 g/mol

Molar mass of hydrogen = 1.0 g/mol

0.00645\times \frac{1molCO_{2}}{44gCO_{2}}\times \frac{1mol\,C}{1mol\,CO_{2}}= 1

0.00151\times \frac{1molH_{2}O}{44gH_{2}O}\times \frac{2mol\,H}{1mol\,H_{2}O}= 1.4

1:1.4

Those two values are multiplied by two.(molar ratio -7)

1:1.4\times 7= 7:8

Therefore, empirical formula - C_{7}H_{8}

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Given the equation: 2H2 + O2 → 2H2O, how many moles of oxygen are needed to react with 13 moles of hydrogen
bulgar [2K]

Explanation:

2H2 + O2 = 2H2O

2mol. 1mol. 2mol

2mol reacts with 1mol

13mol reacts with x

x=<u>13mol</u><u> </u><u>×</u><u> </u><u>1mol</u>

<u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u>2mol</u>

x= <u>13mol</u>

<u> </u><u> </u><u> </u><u> </u><u> </u><u> </u>2mol

x= 6.5mol of oxygen

6 0
2 years ago
True or False?<br><br> Density of ocean water is not affected by salinity (salt content).
Nastasia [14]

Answer:

false

Explanation:

8 0
3 years ago
Read 2 more answers
What is the term for substances that prevent drastic changes in pH
Kay [80]

Answer:

It is termed a buffering agent

Explanation:

A buffering agent consist of a weak acid and a base that is used to maintain the acidity of a solution after the addition of

another acid or base

A buffer is used to prevent any rapid change in ph

5 0
3 years ago
When oxygen and calcium form an ionic bond, what is the formula? o2ca2 oca ca2o2 cao
DIA [1.3K]
Calcium has a 2+ charge and Oxygen has a 2- charge.

To get the formula you have to balance the charges so that it's neutral. In this case a 2- and 2+ charge cancel each other out making the formula CaO.
6 0
3 years ago
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In an experiment to determine the empirical formula of magnesium chloride, 0.50 g of magnesium ribbon was taken in a beaker and
Neporo4naja [7]

Answer:

The the empirical formula for magnesium chloride based on this experiment will be MgCl_{2}

Explanation:

Given that,

Mass of Mg = 0.50 g

Mass of magnesium chloride found = 1.99 g

Let the formula of magnesium chloride be Mg_{x}Cl_{y}

We know that,

Molar mass of Mg= 24 g/mol

Molar mass of magnesium chloride = (24x+35.5y) g/mol

We need to calculate the moles of Mg

Using formula of moles

Number\ of\ moles=\dfrac{mass}{molar\ mass\ of\ Mg}

Put the value into the formula

Number\ of\ moles=\dfrac{0.50}{24}

Number\ of\ moles=0.020\ mole

We need to calculate the mole of magnesium chloride

Using formula of moles

Number\ of\ moles=\dfrac{mass}{molar\ mass\ of\ magnesium\ chloride}

Put the value into the formula

Number\ of\ moles=\dfrac{1.99}{24x+35.5y}\ mole

The reaction will be,

Mg+HCl\Rightarrow Mg_{x}Cl_{y}+H_{2}

We need to calculate the value of x and y

Using number of moles of Mg in reactant and product

Moles of Mg atom in reactant=Moles of Mg atom in product

\dfrac{0.50}{24}=x\times\dfrac{1.99}{24x+35.5y}

0.020(24x+35.5y)=x\times1.99

0.48x+0.71y=1.99x

0.71y=(1.99-0.48)x

\dfrac{x}{y}=\dfrac{0.71}{1.99-0.48}

\dfrac{x}{y}=0.47\approx0.5

\dfrac{x}{y}=\dfrac{1}{2}

Hence, The the empirical formula for magnesium chloride based on this experiment will be MgCl_{2}

7 0
3 years ago
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