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nika2105 [10]
3 years ago
12

Which characteristic do electronegativity differences indicate about reactions between atoms

Chemistry
1 answer:
emmasim [6.3K]3 years ago
6 0
O valence electron number is the answer
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Interstellar clouds are primarily composed of nitrogen and oxygen. true or false?
astra-53 [7]

Answer:

The statement is false

Explanation:

Interstellar clouds are not primarily composed of nitrogen and oxygen. Interstellar clouds are generally an made up of gas, plasma, and dust in our and other galaxies.

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3 years ago
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You have a 0.8 L of a 0.5 M HCl solution. How many moles of HCl does this solution contain?
lions [1.4K]

Answer:

\boxed {\boxed {\sf 0.4 \ mol \ HCl}}

Explanation:

Molarity is concentration measured in moles per liters. It is the number of moles of solute per liters of solution. The formula is:

molarity= \frac{moles \ of \ solute}{liters \ of \ solution}}

We know the solution of HCl has a molarity of 0.5 molar and there are 0.8 liters of solution.

  • 1 molar (M) is equal to 1 mole per liter.
  • Let's convert the molarity of 0.5 M HCl to 0.5 mol HCl per liter. This will make unit cancellation easier.

The moles of solute or HCl are unknown, so we can use x. Now, we can substitute all known values into the formula.

0.5 \ mol \ HCl /L  = \frac {x}{0.8 \ L}

Since we are solving for the moles of solute (x), we must isolate the variable. It is being divided by 0.8 liters. The inverse of division is multiplication, so we multiply both sides by 0.8 L.

0.8 \ L *0.5 \ mol \ HCl /L  = \frac {x}{0.8 \ L} *0.8 \ L

0.8 \ L *0.5 \ mol \ HCl /L=x

The units of liters (L) cancel.

0.8 * 0.5 \ mol \ HCl= x

0.4 \ mol \ HCl=x

This solution contains <u>0.4 moles of HCl.</u>

6 0
3 years ago
To test the effectiveness of a gunpowder mixture, 1 gram was exploded under controlled STP conditions, and the reaction chamber
weeeeeb [17]

<u>Given:</u>

STP (initial) conditions where: P1 = 1 atm and T1 = 298 K

Volume of gas V1 = 310 cm3

Final conditions:

P1 = 2.1 atm

T2 = 2200 + 273 = 2473 K

<u>To determine:</u>

The final volume (V2) occupied by the gas

<u>Explanation:</u>

Using the combined gas law relation:-

P1V1/T1 = P2V2/T2

V2 = (P1V1/T1)(T2/P2)

    = (1*310/298)(2473/2.1) = 1225 cm3

Ans: The volume occupied by the gas under uncontrolled explosion is 1225 cm3



4 0
3 years ago
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