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nika2105 [10]
3 years ago
12

Which characteristic do electronegativity differences indicate about reactions between atoms

Chemistry
1 answer:
emmasim [6.3K]3 years ago
6 0
O valence electron number is the answer
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An unknown element, X, reacts with sodium to form the compound Na2X. In other compounds, this element also can accommodate up to
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B. O

Explanation:

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Tropical rain forests are being cut down to create farms and pastures, and to harvest trees for construction. What has this type
Mrrafil [7]

The deforestation of tropical rainforest trees to create farms and pastures, and to harvest trees for construction has increased soil erosion.

<h3>WHAT IS DEFORESTATION:</h3>
  • Deforestation is the process whereby trees are cut down for commercial purposes e.g. lumbering for paper production.

  • Rainforest is a vegetation characterized by trees and shrubs. However, these trees serve as soil cover and help prevent soil erosion.

This means that deforestation of tropical rainforest trees to create farms and pastures, and to harvest trees for construction has increased soil erosion

Learn more about deforestation at: brainly.com/question/11697527

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2 years ago
Why is refraction so important in eyeglasses.
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What is the most likely meaning of concentration in paragraph 7?thinking thinking about about one one thing thing in in a a focu
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Read 2 more answers
Start with 100.00 mL of 0.10 M acetic acid, CH3COOH. The solution has a pH of 2.87 at 25 oC. a) Calculate the Ka of acetic acid
jasenka [17]

Answer: a) The K_a of acetic acid at 25^0C is 1.82\times 10^{-5}

b) The percent dissociation for the solution is 4.27\times 10^{-3}

Explanation:

CH_3COOH\rightarrow CH_3COO^-H^+

 cM              0             0

c-c\alpha        c\alpha          c\alpha

So dissociation constant will be:

K_a=\frac{(c\alpha)^{2}}{c-c\alpha}

Give c= 0.10 M and \alpha = ?

Also pH=-log[H^+]

2.87=-log[H^+]  

[H^+]=1.35\times 10^{-3}M

[CH_3COO^-]=1.35\times 10^{-3}M

[CH_3COOH]=(0.10M-1.35\times 10^{-3}=0.09806M

Putting in the values we get:

K_a=\frac{(1.35\times 10^{-3})^2}{(0.09806)}

K_a=1.82\times 10^{-5}

b)  \alpha=\sqrt\frac{K_a}{c}

\alpha=\sqrt\frac{1.82\times 10^{-5}}{0.10}

\alpha=4.27\times 10^{-5}

\% \alpha=4.27\times 10^{-5}\times 100=4.27\times 10^{-3}

5 0
3 years ago
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