When you drive your car, you use the gasoline to produce energy which exerts the oil thay was put into the car, would then from it into a cloud or puff of gas which pollutes the air, rises through the atmosphere, and eats away at the Ozone Layer.
P = 2.00 atm = 2026.50hPa
T = 27°C = 300K
m = 14.0g |
Mr = 28g/mol | n = m/M = 14g/28g/mol = 0,5mol
R = 83.1 [hPa*L]/[mol*K]
pV = nRT
nRT 0,5mol * 83.1[hPa*L]/[mol*K] * 300K
V = ---------- = ----------------------------------------------------------- = <u>6.15L</u>
p 2026.5hPa
Answer B.
You add them and then subtract them
Answer:
1120 gm
Explanation:
6. Consider the reaction: CzHo (g) + 02 (8) - 4 CO2(g) + 6H2O (1)
(a) Balance the equation.
(b) How many grams of oxygen are required to react with 10 moles of ethane for a complete
combustion reaction?
FIRST, CORRECT THE EQUATION THEN BALANCE
2C2H6(G) + 7O2------------> 4CO2 + 6H2O
so for 10 moles of ethane, we need
7 X 5 = 35 MOLES O2
=35 MOLES O2
O2 HAS A MOLAR MASS OF 2X16 = 32 gm
35 MOLES OF O2 HAS A MASS OF 35 X 32 =1120 gm
Answer:
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Explanation:
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