It gets huge. REALLY BIG....and tastes like jello....
<span>Many countries experienced the baby boom after the World War II ended. The baby boom resulted to the increase in suburbanization which is number 2. The more people/babies born, the more houses are needed. The countries who experienced the baby boom were not large enough to cater the population so mass developments happened.</span>
The question is incomplete, here is the complete question:
Calculate the pH of a solution prepared by dissolving 0.370 mol of formic acid (HCO₂H) and 0.230 mol of sodium formate (NaCO₂H) in water sufficient to yield 1.00 L of solution. The Ka of formic acid is 1.77 × 10⁻⁴
a) 2.099
b) 10.463
c) 3.546
d) 2.307
e) 3.952
<u>Answer:</u> The pH of the solution is 3.546
<u>Explanation:</u>
We are given:
Moles of formic acid = 0.370 moles
Moles of sodium formate = 0.230 moles
Volume of solution = 1 L
To calculate the molarity of solution, we use the equation:

To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:
![pH=pK_a+\log(\frac{[salt]}{[acid]})](https://tex.z-dn.net/?f=pH%3DpK_a%2B%5Clog%28%5Cfrac%7B%5Bsalt%5D%7D%7B%5Bacid%5D%7D%29)
![pH=pK_a+\log(\frac{[HCOONa]}{[HCOOH]})](https://tex.z-dn.net/?f=pH%3DpK_a%2B%5Clog%28%5Cfrac%7B%5BHCOONa%5D%7D%7B%5BHCOOH%5D%7D%29)
= negative logarithm of acid dissociation constant of formic acid = 3.75
![[HCOOH]=\frac{0.370}{1}](https://tex.z-dn.net/?f=%5BHCOOH%5D%3D%5Cfrac%7B0.370%7D%7B1%7D)
pH = ?
Putting values in above equation, we get:

Hence, the pH of the solution is 3.546
The nurse<span> is </span>caring<span> for a </span>client<span> with a temperature of 104.5 degrees Fahrenheit. A health </span>care provider<span> prescribes 500 mg of an antibiotic intravenous While undergoing a soapsuds </span>enema, theclient reports abdominal<span> cramping.</span>
The effective speed (rms) of the oxygen gas is 293.68 m/s.
<h3>
</h3><h3>What is Root-mean-square velocity?</h3>
Root mean square velocity is the square root of the mean of squares of the velocity of individual gas molecules
![v_{rms}=\sqrt[]{\frac{3RT}{M} }](https://tex.z-dn.net/?f=v_%7Brms%7D%3D%5Csqrt%5B%5D%7B%5Cfrac%7B3RT%7D%7BM%7D%20%7D)
<em>where </em>R = universal gas constant
M = molar mass of the gas in kg/mol
T = temperature in Kelvin
According to the ideal gas law,
PV = nRT
RT = 
Substitute in the rms velocity formula,
![v_{rms} = \sqrt[]{\frac{3PV}{nM} }](https://tex.z-dn.net/?f=v_%7Brms%7D%20%3D%20%5Csqrt%5B%5D%7B%5Cfrac%7B3PV%7D%7BnM%7D%20%7D)
P = 92 kPa, V = 10 L, n = 2 moles and M = 32 x 10⁻³ kg/mol
![v_{rms} = \sqrt[]{\frac{3\times92\times10}{2\times32\times10^-^3} }](https://tex.z-dn.net/?f=v_%7Brms%7D%20%3D%20%5Csqrt%5B%5D%7B%5Cfrac%7B3%5Ctimes92%5Ctimes10%7D%7B2%5Ctimes32%5Ctimes10%5E-%5E3%7D%20%7D)
=293.68 m/s
Thus, the effective speed (rms) of O₂ gas is 293.68 m/s.
Learn more about Root-mean-square velocity:
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