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2 years ago

Question 4 (1 point)

Chemistry

1 answer:

MArishka [77]2 years ago

7 0

The tongue depressor will float on water because its density is less than that of water.

<h3>When do substances sink or float in a liquid?</h3>

Substance will either float or sink in a liquid depending on the comparative densities of the substance and the liquid.

A substance will float in a liquid if it is less dense than the liquid.

A substance will sink in a liquid if it is denser than the liquid.

The density of the tongue depressor = 4.54/6.78 = 0.67 g/cm³

The density of water is 1 g/cm³.

Therefore, the tongue depressor will float on water.

In conclusion, the density of substances determines whether thy float or sink in water.

Learn more about density at: brainly.com/question/952755

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What is the HONC 1234 rule

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The HONC 1234 rule is a way to remember the bonding tendencies of hydrogen, oxygen, nitrogen, and carbon atoms in molecules. Hydrogen tends to form one bond, oxygen two, nitrogen three and carbon four.

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3 years ago

Write the balanced equation for the reaction of aqueous Pb ( ClO 3 ) 2 with aqueous NaI . Include phases. chemical equation: Wha

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<u>Answer:</u> The mass of lead iodide produced is 9.22 grams

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Molarity of NaI = 0.200 M

Volume of solution = 0.200 L

Putting values in above equation, we get:

$0.200M=\frac{\text{Moles of NaI}}{0.200}\\\\\text{Moles of NaI}=(0.200mol/L\times 0.200L)=0.04moles$

The chemical equation for the reaction of NaI and lead chlorate follows:

$Pb(ClO_3)_2(aq.)+2NaI(aq.)\rightarrow PbI_2(s)+2NaClO_3(aq.)$

By Stoichiometry of the reaction:

2 moles of NaI reacts produces 1 mole of lead iodide

So, 0.04 moles of NaI will react with = $\frac{1}{2}\times 0.04=0.02mol$ of lead iodide

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Molar mass of lead iodide = 461 g/mol

Moles of lead iodide= 0.02 moles

Putting values in above equation, we get:

$0.02mol=\frac{\text{Mass of lead iodide}}{461g/mol}\\\\\text{Mass of lead iodide}=(0.02mol\times 461g/mol)=9.22g$

Hence, the mass of lead iodide produced is 9.22 grams

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3 years ago

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3 years ago

If molar mass of M(OH)3 = 78 8. mass of M

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Answer:

From molar mass=total RAM of each individual element

78.8=(16+1)×3+M

78.8-51=M

27.8g/mol=M

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3 years ago