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Harman [31]
3 years ago
11

YALL I NEED HELP ASAP

Chemistry
1 answer:
masya89 [10]3 years ago
6 0

Answer:

Yes

Explanation:

 

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A standard solution of FeSCN2+ is prepared by combining 9.0 mL of 0.20 M Fe(NO3)3 with 1.0 mL of 0.0020 M KSCN . The standard so
Xelga [282]

Answer : The equilibrium concentration of SCN^- in the trial solution is 4.58\times 10^{-8}M

Explanation :

First we have to calculate the initial moles of Fe^{3+} and SCN^-.

\text{Moles of }Fe^{3+}=\text{Concentration of }Fe^{3+}\times \text{Volume of solution}

\text{Moles of }Fe^{3+}=0.20M\times 9.0mL=1.8mmol

and,

\text{Moles of }SCN^-=\text{Concentration of }SCN^-\times \text{Volume of solution}

\text{Moles of }SCN^-=0.0020M\times 1.0mL=0.0020mmol

The given balanced chemical reaction is,

Fe^{3+}(aq)+SCN^-(aq)\rightleftharpoons FeSCN^{2+}(aq)

Since 1 mole of Fe^{3+} reacts with 1 mole of SCN^- to give 1 mole of FeSCN^{2+}

The limiting reagent is, SCN^-

So, the number of moles of FeSCN^{2+} = 0.0020 mmole

Now we have to calculate the concentration of FeSCN^{2+}.

\text{Concentration of }FeSCN^{2+}=\frac{0.0020mmol}{9.0mL+1.0mL}=0.00020M

Using Beer-Lambert's law :

A=\epsilon \times C\times l

where,

A = absorbance of solution

C = concentration of solution

l = path length

\epsilon = molar absorptivity coefficient

\epsilon and l are same for stock solution and dilute solution. So,

\epsilon l=\frac{A}{C}=\frac{0.480}{0.00020M}=2400M^{-1}

For trial solution:

The equilibrium concentration of SCN^- is,

[SCN^-]_{eqm}=[SCN^-]_{initial}-[FeSCN^{2+}]

[SCN^-]_{initial} = 0.00050 M

Now calculate the [FeSCN^{2+}].

C=\frac{A}{\epsilon l}=\frac{0.220}{2400M^{-1}}=9.17\times 10^{-5}M

Now calculate the concentration of SCN^-.

[SCN^-]_{eqm}=[SCN^-]_{initial}-[FeSCN^{2+}]

[SCN^-]_{eqm}=(0.00050M)-(9.17\times 10^{-5}M)

[SCN^-]_{eqm}=4.58\times 10^{-8}M

Therefore, the equilibrium concentration of SCN^- in the trial solution is 4.58\times 10^{-8}M

5 0
3 years ago
What is the mole ratio to correct balance the reaction below? __KBr + __Ca3N2--> __CaBr2 + __K3N
jonny [76]

Explanation:

3CaBr2 + 2K3N → 6KBr + Ca3N2

7 0
3 years ago
2 Holts
Luda [366]

A. They are the most destructive earthquake waves.

D. They can move in a rolling pattern through rock, like an ocean  wave.

Explanation:

Surface waves are seismic waves that cause the most destruction during an earthquake.

Rayleigh waves are known to cause rolling pattern of rocks just like an ocean waves.

  • Seismic waves are elastic waves that notably transmits energy.
  • They usually accompany earthquakes.
  • There are two broad categories of these waves.
  • Surface and body waves.
  • Seismic surface waves are low frequency and long wavelength waves.
  • They travel very close to the surface.
  • They are made up of Love and Rayleigh waves.
  • Love waves travels laterally in a horizontal fashion.
  • Rayleigh waves rolls like ocean waves in the ground.
  • The bulk of the destruction caused during an earthquakes is due to these waves.
  • They are the last waves to arrive a seismic station

learn more:

Seismograph brainly.com/question/11292835

#learnwithBrainly

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What is difference between layer A and layer b? ​
lakkis [162]

Answer:

can you send me a picture of what layer a and look b look like and then I will be able to evaluate

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2 years ago
I created a typical vinegar and baking soda experiment. About 100 ml of white vinegar, and 100ml of baking soda. Once the reacti
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It is 20 because then you will put 30 inside of 20milimeeter and put 70 years into the other pint and put it learnt into the cup
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