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3 years ago

How much heat must be transferred to 1600 g of iron to change the iron's

Chemistry

1 answer:

Artemon [7]3 years ago

4 0

Answer:

A. 8600 J

General Formulas and Concepts:

Thermochemistry

Specific Heat Formula: q = mcΔT

q is heat (in J)
m is mass (in g)
c is specific heat (in J/g °C)
ΔT is change in temperature (in °C)

Explanation:

Step 1: Define

[Given] m = 1600 g

[Given] ΔT = 214 °C - 202 °C = 12 °C

[Given] c = 0.450 J/g °C

[Solve] q

Step 2: Find Heat

Substitute in variables [Specific Heat Formula]: q = (1600 g)(0.450 J/g °C)(12 °C)
Multiply [Cancel out units]: q = (720 J/°C)(12 °C)
Multiply [Cancel out units]: q = 8640 J

Step 3: Check

Follow sig fig rules and round. We are given 2 sig figs as our lowest.

8640 J ≈ 8600 J

Topic: AP Chemistry

Unit: Thermodynamics

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A sample of gas has an intial volume of 22.8 L at a pressure of 1.65 atm. If the sample is compressed to a volume of 10.7 L, wha

almond37 [142]

The pressure of the gas is 3.52 atm

calculation

This is calculated using the Boyle's law formula

that is P1V1= P2V2 where;

P1 = 1.65 atm

V1 =22.8 L

P2 =? atm

V2 = 10.7 L

make P2 the subject of the formula by dividing both side by V2

P2 = P1V1 / V2

P2 = (1.65 atm x 22.8 l) / 10.7 L = 3.52 atm

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3 years ago

What mass of CO is needed to react completely with55.0 g of Fe2O3(s)+CO(g) yield Fe(s)+CO2(g)?

Katarina [22]

Answer:

28.9 g

Explanation:

We know that we will need a balanced equation with masses, moles, and molar masses of the compounds involved.

Gather all the information in one place with molar masses above the formulas and masses below them.

$M_{r}$ : 159.69 28.01

Fe₂O₃ + 3CO ⟶ 2Fe + 3CO₂

Mass/g: 55.0

1. Use the molar mass of Fe₂O₃ to calculate the moles of Fe₂O₃.

$\text{Moles of Fe$_{2}$O$_{3}$} =\text{55.0 g Fe$_{2}$O$_{3}$} \times \frac{\text{1 mol Fe$_{2}$O$_{3}$}}{\text{159.69 g Fe$_{2}$O$_{3}$}}= \text{0.3444 mol Fe$_{2}$O$_{3}$}$

2. Use the molar ratio of CO:Fe₂O₃ to calculate the moles of CO.

$\text{Moles of CO} = \text{0.3444 mol Fe$_{2}$O$_{3}$} \times \frac{\text{3 mol CO}}{\text{1 mol Fe$_{2}$O$_{3}$}}= \text{1.033 mol CO}$

3.Use the molar mass of CO to calculate the mass of CO.

$\text{Mass of CO} = \text{1.033 mol CO} \times \frac{\text{28.01 g CO} }{\text{1 mol CO}}= \textbf{28.9 g CO}$

3 0

3 years ago

Read 2 more answers

List six elements with only 1 electron in an s orbital

Verdich [7]

Answer:

$Lithium=Li2s^1\\Sodium=Na3s^1\\Potassium=K4s^1\\Rubidium=Rb5s^1\\Cesium=Cs6s^1\\Francium=Fr7s^1$

Explanation:

When it comes to electron configuration and orbitals, it's important to first identify what exactly we are trying to identify. Below is a given example:

$He1s^2$