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user100 [1]
1 year ago
11

(a) Is a weak Brønsted-Lowry base necessarily a weak Lewis base? Explain with an example.

Chemistry
1 answer:
anyanavicka [17]1 year ago
3 0

Yes, all Bronsted-Lowry bases are Lewis bases, however no longer all Lewis bases are Bronsted-Lowry bases.

<h3>What is a susceptible Brønsted-Lowry bases?</h3>

A susceptible Brønsted-Lowry base indicates very little tendency to acquire a proton.

Weak Brønsted-Lowry bases consist of H2O, Cl- and NO3-. For example, the chloride ion is a vulnerable Brønsted-Lowry base:

<h3>What is the distinction between a Brønsted-Lowry base and a Lewis base?</h3>

Whereas the Brønsted-Lowry and the Arrhenius classifications are primarily based on switch of protons, Lewis acidity and basicity are primarily based on the sharing of an electron pair. Lewis acids can be given an electron pair, whilst Lewis bases can donate an electron pair.

Learn more about bases here:

<h3>brainly.com/question/1810086</h3><h3 /><h3>#SPJ4</h3>
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<h3>What is a strong acid?</h3>

A weak acid is one that is able to ionize completely in solution. The acid called chromic acid H2CrO4 is not  able to ionize completely in solution.

We know that a buffer is composed of a weak acid and its salt or a weak base and its salt hence if the acid H2CrO4 is present in a buffer then the other half must be  salt of the acid.

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What is molarity of 47.0 g KCl dissolved in enough water to give 375 mL of solution?
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This question provides us –

  • Weight of \bf  KCl is = 47 g
  • Volume, V = 375 mL

__________________________________________

  • Molar Mass of \bf   KCl –

\qquad \twoheadrightarrow\bf  39.0983 \times 35.453

\qquad \twoheadrightarrow\bf 74.5513

<u>Using formula</u> –

\qquad \purple{\twoheadrightarrow\bf Molarity _{(Solution)} =  \dfrac{ W\times 1000}{MV}}

\qquad \twoheadrightarrow\bf Molarity _{(Solution)}  = \dfrac{ 47 \times 1000}{74.5513\times 375}

\qquad \twoheadrightarrow\bf Molarity _{(Solution)}  = \dfrac{47000}{27956.7375}

\qquad \twoheadrightarrow\bf Molarity _{(Solution)}  = \cancel{\dfrac{47000}{27956.7375}}

\qquad \twoheadrightarrow\bf Molarity _{(Solution)}  = 1.68117M

\qquad \pink{\twoheadrightarrow\bf Molarity _{(Solution)}  = 1.7M}

  • Henceforth, Molarity of the solution is = 1.7M

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