Ask question

Ask question

All categories

3 years ago

12

Can yall help on this ??? Asappp

2 answers:

spayn [35]3 years ago

6 0

I think c is the answer

Vsevolod [243]3 years ago

6 0

I believe it’s make hrapg idk tho

You might be interested in

Please help The sun uses nuclear fusion to generate its energy. In the very distant future, the sun will eventually run out of f

QveST [7]

Answer:

A

Explanation:

the answer is a because the sun cannot stop burning but will rather burn hotter Then decay amongst the atoms in space

5 0

2 years ago

1.Chlorobenzene, C6H5Cl, is used in the production of chemicals such as aspirin and dyes. One way that chlorobenzene is prepared

miv72 [106K]

Answer:

$m_{C_6H_5Cl}=65.7gC_6H_5Cl$

Explanation:

Hello!

In this case, according to the given balanced chemical reaction:

$C_6H_6 (l) + Cl_2 (g) \rightarrow C_6H_5Cl (s) + HCl (g)$

We can see there is 1:1 between benzene and chlorobenzene as the relavant product; thus, since the molar mass of benzene is 78.11 g/mol and that of chlorobenzene is 112.55 g/mol, the theoretical yield for this reaction turns out:

$m_{C_6H_5Cl}=45.6gC_6H_6*\frac{1molC_6H_6}{78.11gC_6H_6 }*\frac{1molC_6H_5Cl}{1molC_6H_6}*\frac{112.55gC_6H_5Cl}{1molC_6H_5Cl} \\\\m_{C_6H_5Cl}=65.7gC_6H_5Cl$

Best regards!

8 0

3 years ago

A compound contains only carbon, hydrogen, nitrogen, and oxygen. Combustion of 0.157g of the compound produced 0.213g of CO2 and

vladimir2022 [97]

Answer:

$C_{7} H_{5}N_{3}O_{6}$

Explanation:

First reaction gives you the number of moles or the mass from Carbon and hydrogen

for carbon:

$0,213gCO_{2} .\frac{1molCO_{2}}{44gCO_{2}} .\frac{1molC}{1molCO_{2}} =0.005molC$

$0.213gCO_{2} .\frac{1molCO_{2}}{44gCO_{2}} .\frac{1molC}{1molCO_{2}} .\frac{12gC}{1molC} = 0.058gC\\$

Analogously for hydrogen:

0.0310g $H_{2}O$ have 0.0034gH or 0.0034mol of H

In the second reaction you can obtain the amount of nitrogen as a percentage and find the mass of N in the first sample.

$0.023gNH_{3} .\frac{1molNH_{3}}{17gNH_{3}} .\frac{1molN}{1molNH_{3}} .\frac{14gN}{1molN} \frac{100}{0.103gsample} =18.4%N$

now

$\frac{18.4gN}{100gsample} .0.157gsample=0.0289gN in the first reaction$

this is equivalet to 0.002mol of N

with this information you can find the mass of oxygen by matter conservation.

$gO=total mass-(gN+gC+gH)=0.157-(0.0289+0.058+0.0034)=0.0666gO$

this is equivalent to 0.004molO

finally you divide all moles obtained between the smaller number of mole (this is mol of H)

$C\frac{0.0048}{0.0034} H\frac{0.0034}{0.0034} N\frac{0.002}{0.0034} O\frac{0.004}{0.0034} =C_{1.4} HN_{0.6} O_{1.2}$

and you can multiply by 5 to obtain: $C_{7} H_{5}N_{3}O_{6}$

4 0

3 years ago

Help me with these two please

prohojiy [21]

Answer:

13.A

14.B?

on 14 i don't know

Explanation:

3 0

3 years ago

Read 2 more answers

Which of the following is the correct scientific notation for 0.000056?

svet-max [94.6K]

Hi,

$0.000056 = 5.6 \times {10}^{ - 5}$

Hope this helps.
r3t40

7 0

3 years ago