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shutvik [7]
4 years ago
13

The state of matter that is able to be compressed is gas liquid solid

Chemistry
2 answers:
Anarel [89]4 years ago
8 0
Gases are easily compressible

Sati [7]4 years ago
7 0

The answer would be gas.

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Why the size of Na+ is smaller then Na <br><br>​
Rufina [12.5K]
Because Na+ has less electrons than Na which means Na+ will be a smaller atom (give me brainliest please)
5 0
3 years ago
A chemical reaction that is expected to form 325.0 gof product only forms 123.8 g of product. What is the percent yield of this
Tasya [4]

Answer:

\boxed {\boxed {\sf A. \ 38.1 \%}}

Explanation:

Percent yield is the ratio of the amount actually produced to how much could theoretically be produced. It is found using this formula:

\% \ yield = \frac{actual \ yield}{theoretical \ yield} *100

For this reaction, the theoretical or expected yield is 325.0 grams. The actual yield is 123.8 grams.

\% \ yield = \frac{ 123.8 \ g }{325.0 \ g }*100

Divide.

\% \ yield = 0.380923077 *100

\% \ yield = 38.0923077

Round to the nearest hundredth. The 9 in the hundredth place tells us to round the 0 to a 1 .

\% \ yield \approx 38.1

The percent yield is about <u>38.1%</u>

5 0
3 years ago
Read 2 more answers
If a 0.4681 g Mg strip reacts with 0.650 M HCl in a 139.3 mL flask at 25oC, what is the minimum volume (mL) of HCl needed to com
Marizza181 [45]
The reaction between the magnesium, Mg, and the hydrochloric acid, HCl is given in the equation below,

    Mg + 2HCl --> H2 + MgCl2

The number of moles of HCl that is needed for the reaction is calculated below.
    n = (0.4681 g Mg)(1 mol Mg/24.305 g Mg)(2 mol HCl/1 mol Mg)
    n = 0.0385 mols HCl

From the given concentration, we calculate for the required volume. 
    V = 0.0385 mols HCl/(0.650 mols/L)
     V = 0.05926 L or 59.26 mL

<em>Answer: 59.26 mL of HCl</em>
7 0
3 years ago
Which of the following is NOT a limiting factor for the number of possible compounds?
babymother [125]

Answer:

all elements have a different atomic number

Explanation:

Atomic number of element does not affect their reactions with others

6 0
3 years ago
A 8.00 L tank at 26.9 C is filled with 5.53 g of dinitrogen difluoride gas and 17.3 g of sulfur hexafluoride gas. You can assume
alexandr402 [8]

Answer:

x_{N_2F_2}= 0.415\\\\x_{SF_6}=0.585

Explanation:

Hello!

In this case, since the mole fraction of both gases in the tank is computed via:

x_{N_2F_2}=\frac{n_{N_2F_2}}{n_{N_2F_2}+n_{SF_6}} \\\\x_{SF_6}=\frac{n_{SF_6}}{n_{N_2F_2}+n_{SF_6}}

It means we need to compute the moles of each gas, just as it is shown down below:

n_{N_2F_2}}=5.53gN_2F_2*\frac{1molN_2F_2}{66.01gN_2F_2} =0.0838molN_2F_2\\\\n_{SF_6}=17.3gSF_6*\frac{1molSF_6}{146.06gSF_6} =0.118molSF_6

Thus, the mole fractions turn out:

x_{N_2F_2}=\frac{0.0838mol}{0.0838mol+0.118mol}= 0.415\\\\x_{SF_6}=\frac{0.0838mol}{0.0838mol+0.0838mol}=0.585

Best regards!

8 0
3 years ago
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