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Alex73 [517]
3 years ago
11

Why do Man holes(road) build by use only circular type??

Chemistry
1 answer:
sashaice [31]3 years ago
7 0

Answer: Manholes are usually round, primarily because roundness is the best shape to resist the compression of the earth; covers are round because they are easier to manufacture than square or rectangular shapes, they are easier to move by rolling, and they can't fall into the opening.

Explanation:

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1. Antarctica is a frozen land, so cold and icy that no trees can grow there. Yet scientists have discovered fossils(remains pre
algol [13]

Answer:

This means that Antarctica once had a warmer climate.

Explanation:

Trees usually grow in warm climates, and Antarctica has little to no plant life.

8 0
3 years ago
Fill in the blank to complete each statement
son4ous [18]

Answer:

1. watershed

2. point

3. nonpoint

Explanation:

The land that supplies water to a river system is called a watershed

Pollution from a single, identifiable source is called point

Pollution that is difficult to link to a particular origin is called  nonpoint

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2 years ago
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Compare the vapor pressure curves of 1-butene and 1-heptene. Explain your reasoning.
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How do kinetic tiles work?
raketka [301]

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7 0
3 years ago
If you assume this reaction is driven to completion because of the large excess of one ion, what is the concentration of [Fe(SCN
viktelen [127]

Answer : The concentration of [Fe(SCN)]^{2+} is, 4.32\times 10^{-4}M

Explanation :

When we assume this reaction is driven to completion because of the large excess of one ion then we are assuming limiting reagent is SCN^- and Fe^{3+} is excess reagent.

First we have to calculate the moles of KSCN.

\text{Moles of }KSCN=\text{Concentration of }KSCN\times \text{Volume of solution}

\text{Moles of }KSCN=0.00180M\times 0.006L=1.08\times 10^{-5}mol

Moles of KSCN = Moles of K^+ = Moles of SCN^- = 1.08\times 10^{-5}mol

Now we have to calculate the concentration of [Fe(SCN)]^{2+}

\text{Concentration of }[Fe(SCN)]^{2+}=\frac{\text{Moles of }[Fe(SCN)]^{2+}}{\text{Volume of solution}}

Total volume of solution = (6.00 + 5.00 + 14.00) = 25.00 mL = 0.025 L

\text{Concentration of }[Fe(SCN)]^{2+}=\frac{1.08\times 10^{-5}mol}{0.025L}=4.32\times 10^{-4}M

Thus, the concentration of [Fe(SCN)]^{2+} is, 4.32\times 10^{-4}M

7 0
3 years ago
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