Weak acids only partially ionize. so the retain part of the original molecule. C
The concentration of [H3O+] will be 6.3 x 
M
<h3>pH</h3>
Mathematically, pH = -log [H+] or -log [H3O+]
With a pH of 13.2:
-log [H3O+] = 13.2
log [H3O+] = -13.2
[H3O+] = 6.3 x M
More on pH can be found here: brainly.com/question/491373
#SPJ1
Lets take 100 g of this compound,
so it is going to be 2.00 g H, 32.7 g S and 65.3 g O.
2.00 g H *1 mol H/1.01 g H ≈ 1.98 mol H
32.7 g S *1 mol S/ 32.1 g S ≈ 1.02 mol S
65.3 g O * 1 mol O/16.0 g O ≈ 4.08 mol O
1.98 mol H : 1.02 mol S : 4.08 mol O = 2 mol H : 1 mol S : 4 mol O
Empirical formula
H2SO4
Answer:
Here are three examples
Explanation:
In a reversible reaction, the conversions of reactants to products and of products to reactants occur at the same time.
Example 1
The reaction of hydrogen and iodine to from hydrogen iodide.
H₂ + I₂ ⇌ 2HI
Example 2
The dissociation of carbonic acid in water to form hydronium and hydrogen carbonate ions
H₂CO₃ + H₂O ⇌ H₃O⁺ + HCO₃⁻
Example 3
The dissociation of dinitrogen tetroxide to nitrogen dioxide.
N₂O₄ ⇌ 2NO₂
