The (w/v)% concentration of vinegar contains 5g of acetic in 100mL of solution is approx 0.5 %
<h3>What is Concentration ?</h3>
The concentration of a chemical substance expresses the amount of a substance present in a mixture.
There are many different ways to express concentration.(w/v)% is one of them.
Given ;
- Mass of solute(acetic acid) is 5.0 g
- Volume of solution is 100.0 mL.
We need to convert the grams of acetic acid to moles ;
Formula of acetic acid is CH₃COOH
Thus,
Molar mass of acetic acid = 2(12.01) + 4(1.01) + 2(16)
= 24.02 + 4.04 + 32
= 60.06 grams per mol
Moles of acetic acid = 5.0/60.06
= 0.083 moles
(w/v)% = 0.083 x 60 / 1000 x 100
= 0.498 %
= 0.5 %
Hence, The (w/v)% concentration of vinegar contains 5g of acetic in 100mL of solution is approx 0.5 %
Learn more about weight percentage here ;
brainly.com/question/22575652
#SPJ1
Answer:
1034.88J
Explanation:
Given that:
mass (m) = 11.2 g, initial temperature = 0°C, final temperature = 22°C, the specific heat capacity of water (C) = 4.2 J/g°C
Temperature difference (ΔT) = final temperature - initial temperature = 22 - 0 = 22°C
The quantity of heat (Q) required to melt the ice can be calculated from the equation:
Q = mCΔT
Q = 11.2 g × 4.2 J/g°C × 22°C
Q = 1034.88J
The equation to be used are:
PM = ρRT
PV = nRT
where
P is pressure, M is molar mass, ρ is density, R is universal gas constant (8.314 J/mol·K), T is absolute temperature, V is volume and n is number of moles
The density of air at 23.5°C, from literature, is 1.19035 kg/m³. Its molar mass is 0.029 kg/mol.
PM = ρRT
P(0.029 kg/mol) = (1.19035 kg/m³)(8.314 J/mol·K)(23.5+273 K)
P = 101,183.9 Pa
n = 0.587 g * 1 kg/1000 g * 1 mol/0.029 kg = 0.02024 mol
(101,183.9 Pa)V = (0.02024 mol)(8.314 J/mol·K)(23.5+273 K)
Solving for V,
V = 4.931×10⁻⁴ m³
Since 1 m³ = 1000 L
V = 4.931×10⁻⁴ m³ * 1000
V = 0.493 L
Answer:
Yes, it is possible. Let us consider an example of two solutions, that is, solution A having 20 percent mass RbCl (rubidium chloride) and solution B is having 15 percent by mass NaCl or sodium chloride.
It is found that solution A is having more concentration in comparison to solution B in terms of mass percent. The formula for mass percent is,
% by mass = mass of solute/mass of solution * 100
Now the formula for molality is,
Molality = weight of solute/molecular weight of solute * 1000/ weight of solvent in grams
Now molality of solution A is,
m = 20/121 * 1000/80 (molecular weight of RbCl is 121 grams per mole)
m = 2.07
Now the molality of solution B is,
m = 15/58.5 * 1000/85
m = 3.02
Therefore, in terms of molality, the solution B is having greater concentration (3.02) in comparison to solution A (2.07).
"The sun radiates radiation in the UV, visible and infra-red regions of the spectrum. <span>When this reaches earth, some is reflected off the atmosphere/ clouds back into space. However, some passes through. UV </span>radiation<span> ionises molecules in the </span>thermosphere<span>, and this is the cause of the aurora." Credits to Google
Happy studying!</span>
