How many formula units (f.u.'s) of GaF3 are present in 145 g of GaF3?
1 answer:
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Answer:
100 mL
Explanation:
The reaction that takes place is:
- CaCO₃ + 2HCl → CaCl₂ + H₂O + CO₂
First we <u>convert 500 mg of CaCO₃ into mmoles</u>, using its <em>molar mass</em>:
- 500 mg ÷ 100 mg/mmol = 5 mmol CaCO₃
Then we <u>convert 5 mmoles of CaCO₃ into HCl mmoles</u>, using the <em>stoichiometric coefficients of the balanced reaction</em>:
- 5 mmol CaCO₃ *
= 10 mmol HCl
Finally we <u>calculate the volume of a 0.10 M HCl solution (such as stomach acid) that would contain 10 mmoles</u>:
- 10 mmol / 0.10 M = 100 mL
Answer:
The name of given molecule is 3-Methylpent-2-ene.
Explanation:
First of all a carbon chain of five carbons was drawn. Then a double bond was made between carbon 3 and 4 (starting from left). A methyl group was drawn at middle carbon which is at position 3.
Molecule sketched was named as,
1) A longest chain containing double bond was selected and numbering was started from the end closest to double bond. Hence,
2-Pentene or Pent-2-ene
2) The position of substituent was specified before the parent name, Hence,
3-Methyl-2-Pentene or 3-Methylpent-2-ene
The name of given molecule is 3-Methylpent-2-ene.
Explanation:
First of all a carbon chain of five carbons was drawn. Then a double bond was made between carbon 3 and 4 (starting from left). A methyl group was drawn at middle carbon which is at position 3.
Molecule sketched was named as,
1) A longest chain containing double bond was selected and numbering was started from the end closest to double bond. Hence,
2-Pentene or Pent-2-ene
2) The position of substituent was specified before the parent name, Hence,
3-Methyl-2-Pentene or 3-Methylpent-2-ene