Question

In order to comply with the requirement that energy be conserved, Einstein showed in the photoelectric effect that the energy of a photon (hv) absorbed by a metal is the sum of the work function (Φ), the minimum energy needed to dislodge an electron from the metal’s surface, and the kinetic energy (Eκ) of the electron: hv = Φ + Eκ. When light of wavelength 358.1 nm falls on the surface of potassium metal, the speed (u) of the dislodged electron is 6.403105 m/s.
(a) What is Ek(1/2 mu²) of the dislodged electron?

Answer 1

Based on these findings, Einstein proposed that light behaved as a stream of photons with an energy.

Kinetic energy, Ek = ½mv^2 where m is mass and v is velocity.

Ek = m[v^2 – u^2]/2 and assuming u = 0,

Ek = ½mv^2

What is the photoelectric effect?

When light shines on a metal, electrons are ejected from the metal's surface, causing the photoelectric effect. This is referred to as photoemission, and the electrons released from the metal are referred to as photoelectrons. Photoelectrons behave and have the same properties as ordinary electrons. The photo- prefix simply signifies that incoming light has released electrons from a metal surface.

To explain the photoelectric effect, 19th-century scientists hypothesised that the fluctuating electric field of the incoming light wave heated the electrons and drove them to vibrate, eventually freeing them off the metal surface.

Learn more about photoelectric effect refer:

brainly.com/question/21320305

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