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loris [4]
3 years ago
12

Out of all the states of matter (gas,liquid,plasma,solid) which one to maintain a definite shape?

Chemistry
1 answer:
marissa [1.9K]3 years ago
5 0

the answer would be solid :)

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What is the process of grouping similar things together
andre [41]

Answer:

See Explanation

Explanation:

Mathematically, this means to combine like terms, such as terms with the same variable.  In chemistry, this can refer to polar objects combining with polar objects while nonpolar objects combine with nonpolar objects.

8 0
4 years ago
What are the molarity and osmolarity of a 1-liter solution that contains half a mole of calcium chloride? How many molecules of
givi [52]

Answer:

Molarity = 0.5 M

Osmolarity = 0.5 x 2 = 1 Osmpl.

Molecules of Cl2 = 6.02 x 10^{23} / 4= 1.505 x 10^{23} no. of molecules

Explanation:

If we add half mole in 1L volume than molarity will obviously be 0.5 M.

The osmolarity is molarity multiplies by number of dissociates of solute that for CaCl2 are 2. So, 2 x 0.5 = 1

Half will be molecules of Ca and half will be of Cl2 for 0.5M.

6 0
3 years ago
What’s the compound name for V2(S2O3)3
ohaa [14]

Answer: I HOPE THIS HELPS, HAVE A GREAT EARLY HALLOWEEN

Explanation:

PubChem CID: 1084

Molecular Formula: S2O3(2−) or O3S2-2

Synonyms: Thiosulphate THIOSULFATE ION sulfurothioate UNII-LLT6XV39PY Thiosulfate (S2O32-) More...

Molecular Weight: 112.13 g/mol

7 0
3 years ago
Which of these compounds has the correct chemical formula? 1. ba3po4 2. (nh4)2so4 3. mg2oh 4. lif2 5. caoh?
sergiy2304 [10]
Ba3PO4 is not neutral, it is positive.  (NH4)2SO4 is neutral, the charges cancel.
Mg2OH is not neutral, it is positive.  LiF2 is not neutral, it is negative.  CaOH is not neutral, it is positive.  The answer is (NH4)2SO4, correct ions will have a neutral charge.
4 0
3 years ago
2. How many grams of water can be warmed from 25.0°C to 37.0°C by the addition of 8,064 calories?
sertanlavr [38]

Answer:

672 g

Explanation:

We can calculate the mass of water that can be warmed from 25.0°C to 37.0°C by the addition of 8,064 calories using the following expression.

Q = c \times m \times \Delta T

where,

c: specific heat of the water

m: mass

ΔT: change in the temperature

m = \frac{Q}{c \times \Delta T  }  = \frac{8,064cal}{(1cal/g. \° C) \times (37.0 \° C - 25.0 \° C)  } = 672 g

The mass of water that can be warmed under these conditions is 672 grams.

5 0
3 years ago
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