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kifflom [539]
3 years ago
8

Sedimentary rocks found high in the Himalayan Mountains have been found with fossils of clams and other marine life. What does t

his indicate about the origin of the Himalayan Mountains? A) There was once a large ocean at top of the mountains. B) Animals that now live on the mountains once lived under water. C) The Earth's crust that formed these mountains was once covered with an ocean. Eliminate D) Continental drift resulted two tectonic moving closer to each other over time.
Chemistry
2 answers:
user100 [1]3 years ago
7 0

Answer:

C) The Earth's crust that formed these mountains was once covered with an ocean.

Explanation:

Hello,

In this case, the presence of such sedimentary rocks and fossils demonstrate the earlier existence of an ancient ocean that was covering the Himalayan Mountains due to the found ancient marine life which has no other option to live there because no hint of that type of evolution is available nowadays, therefore, the answer is C) the Earth's crust that formed these mountains was once covered with an ocean.

Best regards.

allochka39001 [22]3 years ago
3 0
C is the answer.

Hope I helped xx
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What does Gibbs free energy depend on? O A. It depends on the rate and quantity of the reaction. O B. It depends on the activati
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C: It depends on the entropy and enthalpy of the reaction.

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Aspirin is a weak organic acid whose molecular formula is HC9H7O4. An aqueous solution of aspirin is prepared by dissolving 3.60
garri49 [273]

Answer:

Ka = 3.50x10⁻⁴

Explanation:

First, we need to convert the unit of 3.60 g/L to mol/L:

C_{C_{9}H_{8}O_{4}} = 3.60 \frac{g}{L}*\frac{1 mol}{180.16 g} = 0.0200 mol/L

The reaction dissociation of aspirin in water is:

C₉H₈O₄  +  H₂O  ⇄  C₉H₇O₄⁻ + H₃O⁺    

0.02 - x                        x             x

The constant of the above reaction is:

Ka = \frac{[C_{9}H_{7}O_{4}^{-}][H_{3}O^{+}]}{[C_{9}H_{8}O_{4}]}

Ka = \frac{x^{2}}{0.02 - x}

To find Ka we need to find the value of x. We know that pH = 2.6 so:

pH = -log[H_{3}O^{+}]

2.6 = -log(x)

x = 2.51 \cdot 10^{-3} M = [H_{3}O^{+}] = [C_{9}H_{7}O_{4}^{-}]

Now, the concentration of C₉H₈O₄ is:

C_{C_{9}H_{8}O_{4}} = 0.02 - 2.51 \cdot 10^{-3} = 0.018 M

Finally, Ka is:

Ka = \frac{[C_{9}H_{7}O_{4}^{-}][H_{3}O^{+}]}{[C_{9}H_{8}O_{4}]} = \frac{(2.51 \cdot 10^{-3})^{2}}{0.018} = 3.50 \cdot 10^{-4}

Therefore, the Ka of aspirin is 3.50x10⁻⁴.

       

I hope it helps you!

3 0
3 years ago
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