A 31.5 g wafer of pure gold initially at 69.4 ∘C is submerged into 63.4 g of water at 27.4 ∘C in an insulated container.
1 answer:
Answer: The final temperature of both substances at thermal equilibrium is 301.0 K
Explanation:
As we know that,
.................(1)
where,
q = heat absorbed or released
= mass of gold = 31.5 g
= mass of water = 63.4 g
= final temperature = ?
= temperature of gold =
= temperature of water =
= specific heat of gold =
= specific heat of water=
Now put all the given values in equation (1), we get
The final temperature of both substances at thermal equilibrium is 301.0 K
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