I know of two ways to solve quadratic equations. The first is through factoring. Let us take the example (x^2)+2x+1=0. We can factor this equation out and the factors would be (x+1)(x+1)=0. To solve for the roots, we equate each factor to 0, that is
x+1=0; x+1=0
In this case, the factors are the same so the root of the equation is
x=1.
The other way is to use the quadratic formula. The quadratic formula is given as [-b(+-)sqrt(b^2-4ac)]/2a where, using our sample equation above, a=1, b=2 and c=1. Substitute these to the formula, and you will get the same answer as the method above.
What is equivalent to 9?
9/1 = 9
9/1 is equivalent to 9.
If your looking for greatest common factors they are 1,67, c,and d.
Answer:
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<em>Answer: check explanation for the solution
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Step-by-step explanation:
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A business that offers services to people by providing many amusement and fun with gate fees
The algebraic equations to be used is the general linear equation
Y = MX + C
Where
Y = total income or money realised
M = rate or price rate
X = number of goods or services
C = flat rate or gate fees
The business can also operate differently by using exponential equation
A = P(1 + R%)^t
Where
A = profit
P = capital
R = rate
t = time
Answer:(7/8 - 4/5)^2 = 9
1600
= 0.005625
Step-by-step explanation:
Subtract: 7
8
- 4
5
= 7 · 5
8 · 5
- 4 · 8
5 · 8
= 35
40
- 32
40
= 35 - 32
40
= 3
40
For adding, subtracting, and comparing fractions, it is suitable to adjust both fractions to a common (equal, identical) denominator. The common denominator you can calculate as the least common multiple of the both denominators - LCM(8, 5) = 40. In practice, it is enough to find the common denominator (not necessarily the lowest) by multiplying the denominators: 8 × 5 = 40. In the next intermediate step the fraction result cannot be further simplified by cancelling.
In words - seven eighths minus four fifths = three fortieths.
Exponentiation: the result of step No. 1 ^ 2 = (3
40
) ^ 2 = 32
402
= 9
1600
In words - three fortieths squared = nine one-thousand six-hundredths.