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guajiro [1.7K]
1 year ago
5

A gas mixture contains ar and h2. what is the total pressure of the mixture, if the mole fraction of h2 is 0. 350 atm and the pr

essure of h2 is 0. 480 atm?
Chemistry
1 answer:
nasty-shy [4]1 year ago
5 0

Considering the Dalton's partial pressure, the total pressure in the mixture of gases is 1.371 atm.

The pressure exerted by a particular gas in a mixture is known as its partial pressure.

So, Dalton's law states that the total pressure of a gas mixture is equal to the sum of the pressures that each gas would exert if it were alone:

P_{T} = P_{1}+P_{2}+......+P_{n}

where n is the amount of gases in the mixture.

Dalton's partial pressure law can also be expressed in terms of the mole fraction of the gas in the mixture.  So in a mixture of two or more gases, the partial pressure of gas A can be expressed as:

P_{A} = X_{a}P_{T}

In this case, the partial pressure of gas H₂ can be expressed as:

P_{H2} = X_{H2} P_{T}

You know:

P_{H2} = 0.48 atm

X_{H2} = 0.35

Replacing in the definition of partial pressure of gas H₂:

0.48atm = 0.35P_{T}

Solving:

P_{T} = \frac{0.48atm}{0.35}

P_{T}= 1.371 atm

In summary, the total pressure in the mixture of gases is 1.371 atm.

Learn more about partial pressure: brainly.com/question/15302032

#SPJ4

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Three 6−l flasks, fixed with pressure gauges and small valves, each contain 6 g of gas at 276 k. flask a contains ch4, flask b c
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First, please check the missing part in your question in the attachment.

a) So first, the Rank of pressure:

according to this formula PV = nRT and when n = m/Mw

PV = m/Mw * R*T

when we have the same mass m and the same V volume so P will proportional with the mole weight M as when the M is smaller the pressure will be greater 

when Mw of H2(A) = 2 g / Mw of He (B) = 4 g and Mw of CH4(C) = 16 g

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 (A) > (B) > (c)

B) The rank of average molecular kinetic energy:

when K = 3/2 KB T

when K is the average kinetic energy per molecule of gas 

and KB is Boltzmann's constant

and T is the temperature (K)

So from this equation, we can know that K only depends on T value, and when we have the T constant here for A, B, and C So the rank of K will be like the following:

∴ A = B = C

C) the rank of diffusion rate after the valve is opened:

according to this formula:

R2/R1 = √M1/M2

from this equation, we can see that diffusion is proportional to the reciprocal of the molecular mass M so,

when Mw H2 (A) = 2 g & Mw He(B) = 4 g & CH4 (C) = 16 g

∴ the rank of diffusion:

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D) The rank of the Total kinetic energy of the molecules:

when we have the Mw different so it will make the no.of molecules differs as when the Mw is low the no.of molecules will be hight, and when the average molecular kinetic energy equals. so the total kinetic energy will depend on no. of molecules 

∵ Mw A < Mw B < Mw C 

∴no .of molecules of A > B >C

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A > B > C

e) the rank of density:

when ρ = m/ v 

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A = B = C

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as the no.of molecules increase the collision frequency increase and depend also on the velocity and it's here the same.

∴ Collision frequency will only depend on the no.of molecules

we have no.of molecules of A > B > C as Mw A < B < C 

∴the rank of the collision frequency is:

A > B > C 

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